Make x the subject
2x = -3y + 1
5x = -2y -3
now times the answers to get the lcd
(2x = -3y + 1) x 5
10x = -15y + 5
(5x = -2y -3) 2
10x = -4y -6
now that they are equal to the same number:
-15y + 5 = -4y -6
-15y + 4y = -6 -5
-11y = -11
y = 1
now to find x we substitute y
2x = -3y + 1
2x = -3(1) + 1
2x = -3 + 1
2x = -2
x = -1
Answer:
Step-by-step explanation:
the polynomial function is; (x - i)(x-2)(x+2)
Segment PQ bisects the angle P, which means angle QPR has a measure of 21 degrees (which follows from the fact that triangles PQR and PQS are congruent and PR and PS are tangent to the circle).
This then means angle RQP has measure 90 - 21 = 69 degrees.
Angle Q is twice this, so it has measure 138 degrees.
Answer: is this an acute im confused
Step-by-step explanation:
Answer:
Step-by-step explanation:
given the expression;
cos(2x) = cos(x)
According to trig identity;
cos(2x) = cos(x+x)
cos(2x) = cos x cos x - sinx sinx
cos(2x) = cos²(x)-sin²(x)
cos(2x) = cos²(x)-(1-cos²x)
cos(2x) = cos²(x)+cos²x-1
cos(2x) = 2cos²(x)-1
2cos²(x)-1 = cos(x)
let P = cosx
2P²-1 = P
2P²-P-1 = 0
Factorize;
2P²-2P+P-1 = 0
2P(P-1)+1(P-1) = 0
2P - 1 = 0 and P-1 = 0
P = 1/2 and 1
cosx = 1/2 and cos x = 1
x = arccos 1/2
x = π/3
Also;
x = arccos1
x = 0
Hence the value of x are 0 and π/3
Also the angle = π+ π/3 = 4π/3
The angles are 0, π/3 and 4π/3
