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3 years ago

Which implementation uses both the legacy system and new system until all users verify that the new system functions correctly?

Computers and Technology

1 answer:

olasank [31]3 years ago

3 0

Answer:

Explanation:

One group of students did an experiment to study the movement of ocean water. The steps of the experiment are listed below.

Fill a rectangular baking glass dish with water.

Place a plastic bag with ice in the water near the left edge of the dish.

Place a lighted lamp near the left edge of the dish so that its light falls directly on the plastic bag.

Put a few drops of ink in the water.

The student did not observe any circulation of ink in the water as expected because the experiment had a flaw. Which of these statements best describes the flaw in the experiment? (2 points)

Not enough ink was added.

Not enough water was taken.

The dish was too small for the experiment.

The lamp and the ice bag were at the same place.

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I think AAAAMMMMMHHVVV

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2 years ago

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QveST [7]

Answer:

Data Mining.

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3 years ago

A technique for identifying and tracking assets using technologies such as RFID and smart cards is known as electronic tagging.

Mademuasel [1]

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3 years ago

Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.

Ede4ka [16]

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

$v = \frac{(xf-xo)}{(t-to)}$

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

$t =\frac{xf}{v} =\frac{2e5 m}{2.3e8 m/s} =8.7e-4 sec.$

⇒ t = 8.7*10⁻⁴ sec.

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3 years ago

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The answer is E: all of the above.

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2 years ago