Answer:
OphCrack LiveCD.
Explanation:
The user examines that server of a client, as well as requires complete control of such a system. To avoid recognizing its invasion by certain security programs, he wants to select a LiveCD which can break Operating System's credentials, and he would have been using OphCrack LiveCD because it used to crack the credential of the Windows user.
So, the following are the reason by which the answer is correct according to the scenario.
Compaction often gives solutions to the issues regarding external fragmentation.
One technique for overcoming external fragmentation in dynamic partitioning is
Compaction.
The reason why this technique of overcoming external fragmentation may be inefficient is because:
- External fragmentation may need a lot of compaction and it is an expensive operation.
- The use of contiguous allocation is often hard to fit processes into memory and also it is so difficult to grow or shrink the amount of memory allocated to a process.
- Compaction only takes place when relocation is dynamic, and this also is expensive.
Compaction often shuffle memory notes or contents and then put or pile them up all in free memory and in one large block.
External fragmentation takes place when free memory is removed into small blocks.
Learn more from
brainly.com/question/23636593
Answer:
The solution is implemented using C++
int getRowTotal(int a[][5], int row) {
int sum = 0;
for(int i =0;i<5;i++)
{
sum += a[row][i];
}
return sum;
}
Explanation:
This defines the getRow function and the parameters are arr (the 2 d array) and row and integer variable
int getRowTotal(int arr[][5], int row) {
This defines and initializes sum to 0
int sum = 0;
This iterates through the row and adds the row items
<em> for(int i =0;i<5;i++) {
</em>
<em> sum += arr[row][i];
</em>
<em> }
</em>
This returns the calculated sum
return sum;
}
D. Writing the methods of the classes
I think it’s what the other person said
