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Margarita [4]
3 years ago
15

Graph both functions to find the solution(s) to the system. {f(x)=x+1 g(x)=x2−6x−7   Use the line tool to graph the line. Use th

e parabola tool to graph the parabola. Choose maximum or minimum point first and then a point on the parabola.

Mathematics
2 answers:
ivanzaharov [21]3 years ago
7 0

Answer:

For the line, plot the points: <em>( 8, 9 ) </em>& <em>( -1, 0 )</em>

<em></em>

For the parabola, plot the points: ( <em>3, 16 ) </em>& <em>( 8, 9 )</em>

<em></em>

<em>This is the correct answer! I just took the test!! Good luck!</em>

Strike441 [17]3 years ago
5 0

Answer:

solutions to f(x)=g(x) are x=-1 and x=8

Step-by-step explanation:

The minimum point of the parabola will be found at ...

x = -b/(2a) . . . . . where a, b, c are the coefficients of ax²+bx+c

For g(x) = x² -6x -7, the minimum will be at x=-(-6)/(2·1) = 3. The minimum value is ...

g(3) = 3² -6·3 -7 = -16

so the vertex (minimum point) you want to plot is (3, -16). Since the coefficient of x² is 1, there is no vertical scaling, so when the value of x differs from 3 by 1 unit, the value of g(x) will be 1² = 1 unit higher. That is, g(4) = -15, so (4, -15) is another point on the parabola.

___

I find it convenient to use a graphing calculator for the whole problem.

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cupoosta [38]

Answer:

t=(15-1) [\frac{0.219}{0.2}]^2 =16.7864

p_v = 2*P(\chi^2_{14}>16.786)=0.5355

And the 2 is because we are conducting a bilateral test.

\alpha=0.05 since the the p_v >0.05 we fail to reject the null hypothesis.

\alpha=0.01 since the the p_v >0.01 we fail to reject the null hypothesis.

Step-by-step explanation:

Data given

\mu=7 population mean (variable of interest)

\sigma=0.2 represent the population standard deviation

s=0.219 represent the sample deviation

n=15 represent the sample size

\alpha=0.05,0.01 represent the values for the significance level  

Hypothesis test

On this case we want to check if the population standard deviation is equal or not to 0.2, so the system of hypothesis are:

H0: \sigma = 0.2

H1: \sigma \neq 0.2

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(15-1) [\frac{0.219}{0.2}]^2 =16.7864

P value

We know the degrees of freedom of the distribution 14 on this case and we can find the p value like this:

p_v = 2*P(\chi^2_{14}>16.786)=0.5355

And the 2 is because we are conducting a bilateral test.

\alpha=0.05 since the the p_v >0.05 we fail to reject the null hypothesis.

\alpha=0.01 since the the p_v >0.01 we fail to reject the null hypothesis.

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4 years ago
Y=5/2x−8
Levart [38]
One solution: (0,-8) is the answer
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x/3 =  (y + 2)/2 - 1

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x/3 = (y + 2 - 2)/2

x/3 = y/2

Therefore the correct answer is x/3 = y/2

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