We know that g(x) = \frac{3}{x^2+2x}
We have to find g^-1(x) or inverse of g(x)
Inverse of g(x) can be determined by equating g(x) to y, and determining the value of x in terms of y
g(x) = y = \frac{3}{x^2+2x}
⇒ y × (x² + 2x) = 3
⇒ yx² + 2xy = 3
⇒ yx² + 2yx - 3 = 0
Determining the roots of x using:
x =
OR x =
, where a is coefficient of x², b is coefficient of x, and c is the constant
⇒ x =
OR x = 
⇒ x =
OR x = 
Hence, g^-1(x) =
OR x = 
Answer:
5/y^3
Step-by-step explanation:
Answer:
the new equation is f(x)=x^2-4
vertex- (0,-4)
zeros- (-2,2)
y-intercept- (-4)
and it has a minimum
Answer:
There is no picture
Step-by-step explanation: