Answer:
P (H₂) = 741 torr
Explanation:
Let's begin by listing out the given parameters:
Temperature (water) = 298 K, volume = 45.6 mL,
atmospheric pressure, P (total) = 765 torr, vapor pressure of water, P (H₂O) = 24 torr
To get the pressure of inside the tube, P (H₂), we apply Dalton's Law of Partial Pressure and we have:
P (total) = P (H₂) + P (H₂O)
P (total) = 765 torr, P (H₂O) = 24 torr
P (H₂) = P (total) - P (H₂O) = 765 - 24
P (H₂) = 741 torr
It therefore becomes clear that the pressure of H₂(g) is 741 torr
Hi!
Electrons are particles which basically 'orbit' around the nucleus. Protons and neutrons are condensed, in a fixed position inside the nucleus.
With this in mind, the answer will be C.
Hopefully, this helps! =)
Answer:
26.67 mol HCl
Explanation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
In order to solve this problem, we need to c<u>onvert Al(OH)₃ moles to HCl moles</u>.
To do so we use the<em> stoichiometric ratios</em> of the balanced reaction:
- 8.89 mol Al(OH)₃ *
= 26.67 mol HCl
Thus 26.67 moles of HCl would react completely with 8.89 moles of Al(OH)₃.
Explanation:
Start with a balanced equation.
2H2 + O2 → 2H2O
Assuming that H2 is in excess, multiply the given moles H2O by the mole ratio between O2 and H2O in the balanced equation so that moles H2O cancel.
5 mol H2O × (1 mol O2/2 mol H2O) = 2.5 mol O2
Answer: 2.5 mol O2 are needed to make 5 mol H2O, assuming H2 is in excess.
Answer:
<em><u>general formula RCOX, where R represents an alkyl or aryl organic radical group, CO ... represents a halogen atom such as chlorine ... loss of a hydroxyl group (-OH), viz, acetyl,. CH, CO- ..</u></em>
