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aev [14]
3 years ago
13

How many grams of potassium chloride are required to make 250 ml of a 0.75 m kcl solution?

Chemistry
1 answer:
DedPeter [7]3 years ago
7 0

Answer:

The solution would need 13.9 g of KCl

Explanation:

0.75 m, means molal concentration

0.75 moles in 1 kg of solvent.

Let's think as an aqueous solution.

250 mL = 250 g, cause water density (1g/mL)

1000 g have 0.75 moles of solute

250 g will have (0.75 . 250)/1000 = 0.1875 moles of KCl

Let's convert that moles in mass (mol . molar mass)

0.1875 m . 74.55 g/m = 13.9 g

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The concentration of a saturated solution of an ionic compound at 25 oC is 7.00E-4. The formula for this compound is XQ3. What i
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Answer:

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Explanation:

The Solubility of the Ionic compound is given by s

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solubility equation is given as follows

                     XQ₃(s)           ⇄           X³⁺(aq)          +          3Q⁻(aq)

                         s                                s                               3s

let the concentration of each be s

The concentration of Q = 3s

⇒                                [Q] = 3 × 7 × 10⁻⁴ mol/dm³

⇒                                [Q] = 2.1 × 10⁻³ mol/dm³

hence,

                                   Ksp =      [X³⁺][Q⁻]³

                                   Ksp =      [s][3s]³

                                   Ksp =      [7 × 10⁻⁴ ][2.1 × 10⁻³]³

                                   Ksp =      1.57 × 10⁻¹² mol/dm³

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