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madreJ [45]
3 years ago
12

Which of the following is the correct skeleton equation for the reaction that takes place when solid phosphorus combines with ox

ygen gas to form diphosphorus pentoxide?
A. P(s) + O2(g) --> P2O5(s)

B. P2O5(s) --> P2(s) + O2(g)

C. P(s) + O(g) --> P5O2(g)

D. P(s) + O2(g) --> PO2(g)
Chemistry
1 answer:
Aliun [14]3 years ago
4 0

Answer: Option (A) is correct.

Explanation:

In diphosphorus pentoxide there will be two phosphorous atoms and 5 oxygen atoms according to its name.

Therefore, the formula for diphosphorus pentoxide will be P_{2}O_{5} and it is a solid.

Thus, the correct skeleton equation for the reaction that takes place when solid phosphorus combines with oxygen gas to form diphosphorus pentoxide will be as follows.

                 P(s)+ O_{2}(g) \rightarrow P_{2}O_{5}(s)


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TV and radio stations transmit in specific frequency bands of the radio region of the electromagnetic spectrum.
Elodia [21]

Answer:

a) Yes, these bands of signals overlap.

b) FM has broader transmission band.

Explanation:

a) Frequency range of TV channels = 59.5 to 215.8 MHz

Wavelength range of FM radio = 2.78 m to 3.41 m

Frequency of the wave = \nu

Wavelength of the wave = \lambda

Speed of light = c = 3\times 10^8 m/s

\nu =\frac{c}{\lambda }

Frequency of wave with, \lambda = 2.78 m

\nu =\frac{3\times 10^8 m/s}{2.78 m}=1.079\times 10^8 Hz

1.079\times 10^8 Hz=1.079\times 10^8\times 10^{-6} MHz=107.9 MHz

Frequency of wave with, \lambda = 3.41m

\nu =\frac{3\times 10^8 m/s}{3.41 m}=8.798\times 10^7 Hz

8.798\times 10^7 Hz=8.798\times 10^7\times 10^{-6} MHz=87.98 MHz

Frequency range of FM = 87.89 to 107.9 MHz

Frequency range of TV channels = 59.5 to 215.8 MHz

Yes, these bands of signals overlap.

b)  

Frequency range of AM = 550 to 1600 kHz

1 kHz = 0.001 MHz

550 to 1600 kHz = 550\times 0.001 MHz to 1600\times 0.001 MHz

= 0.55 MHz to 1.6 MHz

Frequency range of AM = 0.55 to 1.6 MHz

Frequency range of FM = 87.89 to 107.9 MHz

FM has broader transmission band.

4 0
3 years ago
Hi! please help me identify the IUPAC name for the structures ​
Snowcat [4.5K]

The IUPAC names of the organic compounds would be as follows:

1. Methanol or 1-Methanol

2. Propan-2-ol or 2-Propanol

3. 2-MethylButane

4. 1-Hexanol

5. 1-Heptanol

<h3>Naming organic compounds</h3>

In the naming of organic compounds, some fundamental rules come into practice. Some of these rules include:

  • The longest carbon chain, otherwise known as the parent chain, is considered.
  • The substituents must be identified
  • The parent chain should be named such that the substituents are located on the lowest-numbered carbons. Repeated substituents are named accordingly.
  • Different substituents are named alphabetically and substituents with lower alphabets are considered for the lowest-numbered carbons.

Following these rules and more, the name of the organic compounds whose structures are shown in the image would be as follows:

  • Methanol or 1-Methanol
  • Propan-2-ol or 2-Propanol
  • 2-MethylButane
  • 1-Hexanol
  • 1-Heptanol

More on IUPAC naming can be found here: brainly.com/question/16631447

#SPJ1

7 0
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