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<em>1</em><em>.</em><em>259ms^2</em>
Explanation:
since, WORK DONE = FORCE*DISTANCE
AND, FORCE=MASS*ACCELERATION
SO, THE WORK DONE BECOMES=MASS*ACCELERATION*DISTANCE
ACCELERATION=WORK/(MASS*DISTANCE)
AND, WORK=686J
MASS=227kg
DISTANCE=2.4m
THEREFORE, ACCELERATION=686/(227*2.4)
=686/544.8
=1.259ms^2
Since the Units presented are not in the International System we will proceed to convert them. We know that,

So the speed in SI would be


The change in frequency when the wave is reflected is

Or we can rearrange the equation as

f' = Apparent frequency
f = Original Frequency
c = Speed of light


Replacing,


Since the waves are reflected, hence the change in frequency at the gun is equal to twice the change in frequency



Therefore the increase in frequency is 2979.63Hz
Answer:
<em>The rubber band will be stretched 0.02 m.</em>
<em>The work done in stretching is 0.11 J.</em>
Explanation:
Force 1 = 44 N
extension of rubber band = 0.080 m
Force 2 = 11 N
extension = ?
According to Hooke's Law, force applied is proportional to the extension provided elastic limit is not extended.
F = ke
where k = constant of elasticity
e = extension of the material
F = force applied.
For the first case,
44 = 0.080K
K = 44/0.080 = 550 N/m
For the second situation involving the same rubber band
Force = 11 N
e = 550 N/m
11 = 550e
extension e = 11/550 = <em>0.02 m</em>
<em>The work done to stretch the rubber band this far is equal to the potential energy stored within the rubber due to the stretch</em>. This is in line with energy conservation.
potential energy stored = 
==>
= <em>0.11 J</em>
Answer:
reduce the velocity of collision