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pychu [463]
3 years ago
8

The sum of three consecutive integers is 126..............

Mathematics
1 answer:
Rasek [7]3 years ago
6 0
The three consecutive integers are: x, (x+1) and (x+2).
We can suggest this equation:
x+(x+1)+(x+2)=126
3x+3=126
3x=126-3
3x=123
x=123/3
x=41

x=41
(x+1)=41+1=42
(x+2)=41+2=43

Answer: the three consecutive integers would be: 41,42 and 43. 
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9. 85 x s; s = 4 please help
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Step-by-step explanation:

Hi,

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dybincka [34]
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7 0
2 years ago
7 + 3p^2 in standard form
lara31 [8.8K]

Answer:

Step-by-step explanation:

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 7 +  3p2

Step  2  :

Polynomial Roots Calculator :

2.1    Find roots (zeroes) of :       F(p) = 3p2+7

Polynomial Roots Calculator is a set of methods aimed at finding values of  p  for which   F(p)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  p  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  3  and the Trailing Constant is  7.

The factor(s) are:

of the Leading Coefficient :  1,3

of the Trailing Constant :  1 ,7

3p2 + 7

7 0
3 years ago
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