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Elina [12.6K]
3 years ago
7

Operations that run in protected mode must go through which of the following before they can access a computer’s hardware? A. Ke

rnal B. Network C. Device driver D. User Interface
Computers and Technology
1 answer:
HACTEHA [7]3 years ago
3 0

Answer:

Option A (Kernal) seems to be the right answer.

Explanation:

  • A Kernel appears to be the central component of such an OS. This handles machine as well as hardware activities, including most importantly storage as well as CPU power.
  • This manages the majority of the initialization as well as program input/output requests, converting them into CPU data-processing commands.

The other given option are not related to the given circumstances. So that option A would be the right answer.

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Answer:

I think the answer would be 60x something but I'm not for sure

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Consider the following declaration.int[] alpha = new int[3];Which of the following input statements correctly input values into
stepladder [879]

Answer:

Option (2) i.e., Only (ii) is the correct option to the following question.

Explanation:

Here, in the following code that is written in the Java Programming Language in which they set integer data type array variable "alpha" and set its index to 3 through "new" keyword then, we get input from the user in the index 0 then, we get input from the user in the index 1 then, again we repeat this step for index 2. So, that's why the following option is correct.

Option 1 is wrong because in this option the user input only in the index 0 and this is also the wrong way to insert value in the array variable.

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3 years ago
Which technique is used to convert a color image to a black and white image?
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Microscope
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3 years ago
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

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Activities provided for the satisfaction of others and consumed at the time of purchase<br> are…
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