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Anna11 [10]
3 years ago
14

The Earth's _______ is ductile overall, tending to flow very slowly and deform in a _______ manner.

Computers and Technology
2 answers:
kipiarov [429]3 years ago
5 0

<span>The asthenosphere is a part of the upper mantle just below the </span>lithosphere<span> <span>that is involved in </span></span>plate tectonic movement<span> <span>and </span></span>isostatic<span> <span>adjustments. The lithosphere-asthenosphere boundary is conventionally taken at the 1300 °C </span></span>isotherm<span>, above which the mantle behaves in a rigid fashion and below which it behaves in a </span>ductile<span> fashion. a</span><span>nd </span>flows very slowly, in a manner<span> similar to the ice at a bottom of a glacier.</span>

andrew-mc [135]3 years ago
4 0

Answer:

The answer is "lithosphere and brittle"

Explanation:

The word lithosphere is the outermost crust of the earth, which consists of the roast of the planet and the rest of the fur. The tectonic plate, which is also known as the asthenosphere, has fractured mostly.  

The substance brittles when under tension, separates without significant plastic deformations and behaves like a ductile, a shape acting to move very slowly, like the ice at the foot of a glacier.

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Answer:

Probably would use LAN

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Schools use LAN to connect students to their networks, so it would make sense for them to use LAN for offices. They could use ethernet if all their PCs are hard wired in, though.

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Flura [38]

Answer:

The page field is 8-bit wide, then the page size is 256 bytes.

Using the subdivision above, the first level page table points to 1024 2nd  level page tables, each pointing to 256 3rd page tables, each containing 64 pages. The program's address space consists of 1024 pages, thus we need we need 16 third-level page tables. Therefore we need 16 entries in a 2nd level page table, and one entry in the first level page table. Therefore the size is: 1024 entries for the first table, 256 entries for the 2nd level page table, and 16 3rd level page table containing 64 entries each. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 2 (one second-level paget table) + 16 * 64 * 2 (16 third-level page tables) = 4608 bytes.

First, the stack, data and code segments are at addresses that require having 3 page tables entries active in the first level page table. For 64K, you need 256 pages, or 4 third-level page tables. For 600K, you need 2400 pages, or 38 third-level page tables and for 48K you need 192 pages or 3 third-level page tables. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 3 * 2 (3 second-level page tables) + 64 * (38+4+3)* 2 (38 third-level page tables for data segment, 4 for stack and 3 for code segment) = 9344 bytes.

Explanation:

16 E the answer

5 0
3 years ago
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zimovet [89]

Answer:

To make people interested.

Explanation:

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Aleksandr [31]

Answer:

1 will be stored in result

Explanation:

Given

The lines of code

Required

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In the first line, the value of x is 2 and the value of y is 6

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