If it doesnt have a nucleus or a cell wall it is a prokaryote. also prokaryotes displayed in pictures tends to be longer
Answer:
B) a signal-recognition particle that brings ribosomes to a receptor protein in the ER membrane.
Explanation:
Each synthesized protein has to be targeted to the specific location and transported to that location. There are two possible ways for that transport: post-translational transport or co-translational transport.
• Co-translational transport occurs during the process of translation, and proteins transported this way are proteins bound for organelles in the endomembrane system (such as the ER, Golgi apparatus, and lysosome), plasma membrane proteins or proteins for the exterior of the cell. They have an amino sequence called a signal peptide which sends them to ER first.
• Proteins that do not have a signal peptide stay in the cytosol so, their transport is after the translation (post-translational).
The answer is F1 generation
Answer:
b. to amplify the signal
Explanation:
A multi-enzyme phosphorylation cascade is a series of signaling events where one enzyme phosphorylates to another, then this last enzyme acts to phosphorylate another protein and so successively, thereby triggering a chain reaction that leads to the phosphorylation of hundreds or even thousands of proteins. A multi-enzyme phosphorylation cascade is known to increase the number of activated (phosphorylated) proteins at each step of the signaling cascade. Phosphorylation is a posttranslational modification capable of activating proteins during long periods, thereby a phosphorylation cascade also enables the activation of multiple proteins before these proteins become inactive again.
Answer:
0%
Explanation:
Round = Dominant
Wrinkled = recessive
Recessive = r
Dominant = R
homozygous dominant = RR
homozygous recessive = rr
Heterozygous= Rr
Since both seeds are homozygous recessive (rr)
In your punnet square, one lower case r will go on the top and the left side
r r
r
r
Something like that.
Go across your four boxes and you will end up with;
rr, rr
rr, rr
In order for it to be round, at least one box would need to have to be a heterozygous(Rr) or be a homozygous dominant.
