Question

If the diagonal path is 750 feet long and the width of the park is 450 feet, what is the length, in feet, of the park?

Answer 1

Answer:

C, 600 ft.

Step-by-step explanation:

a^2+b^2=c^2

C is always the hypotenuse/diagonal. Let A represent length and B represent width.

A^2+450^2=750^2

A^2+202500=562500

562500-202500=360000=A^2

take the square root of both sides to solve for A and the value of A is 600.

Answer 2

Answer:

600 feet

Step-by-step explanation:

I am assuming that the park is rectangular, and the together, the length, with and diagonal form a right triangle.

In this case, we are given

Diagonal = 750 ft = hypotenuse

Width = 450 feet

Find length L

Using the Pythagorean theorem,

L² + 450² = 750²

L² = 750² - 450² = 360,000

L= √360,000 = 600 feet