Start by taking the information we know, and write equations to represent the realationships:
1) "1/8 lbs less flour to make bread than to make cookies"
![b=c-\frac{1}{8}](https://tex.z-dn.net/?f=%20b%3Dc-%5Cfrac%7B1%7D%7B8%7D)
2) "1/4 lb more flour to make cookies than to make brownies:
![c=w+\frac{1}{4}](https://tex.z-dn.net/?f=%20c%3Dw%2B%5Cfrac%7B1%7D%7B4%7D)
3) "she used 1/2 lb of flour ro make bread"
![b = \frac{1}{2}](https://tex.z-dn.net/?f=%20b%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
From here you can solve for
![w](https://tex.z-dn.net/?f=w)
using back substitution.
Answer:
(
)πr²h
Step-by-step explanation:
Can I see the option or the answer choices?
Answer:
x+x=8
that's mean: 2.x/4 + 4.x/1 = 18/1
we find at least a common multiple of 4 and multiply the units by 4
2x + 16x = 72
18x = 72/:18
x = 4
Answer:The value of the expression increases as r decreases.
Step-by-step explanation:
To find : What happens to the value of the expression as r decreases?
Given Expression: 80-2r
We check for different value of r as decreasing order,
r 80-2r
5 80-10=70
4 80-8=72
3 80-6=74
2 80-4=76
1 80-2=78
As r decreases the value of expression increases.
Therefore, the value of the expression increases as r decreases.
Hope this helps!