Ask question

Ask question

All categories

uranmaximum [27]

3 years ago

15

If we had a Pyramid with a hexagonal base, how many of these pyramids would it take to fill up a hexagonal Prism with a congruen

t base, and equal height?

1 answer:

klemol [59]3 years ago

5 0

Idk what is the answers

You might be interested in

Apply the rules for order of operations to simplify 2+3-4+(5X4)

katovenus [111]

The answer should be 21 hope it helps

5 0

3 years ago

Read 2 more answers

The equation represents an ellipse.

Tom [10]

Answer:

B) (-10, -6) and (8, -6)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How can the bar symbol be used to show the quotient of 7÷11 if the division is carried on forever?

Thepotemich [5.8K]

$\bf 7\div 11\implies 0.636363636363636........\implies 0.\overline{63}$

4 0

3 years ago

Which system of equation should you use to solve this problem

Alex17521 [72]

Last option is the correct answer.

Step-by-step explanation:

Given that

Let x stand for the solution a and y stand for the solution B

So,

According to statement that

30 gallons have to be made

$x+y=30$

Solution A contains 29 percent bromine => 0.29x

Solution B contains 53 percent =>0.53y

And the mixture of 30 gallons contains 45% bromine

$0.29x+0.53y=30*0.45\\0.29x+0.53y=13.5$

Following equations will be used for solving the problem

$x+y = 30\\0.29x+0.53y=13.5$

Hence,

Last option is the correct answer.

Keywords: Equations, Variables

Learn more about linear equations at:

#LearnwithBrainly

4 0

3 years ago

Whats balance fe+30^2 >fe^2O^3

blsea [12.9K]

Answer:

You are given:

4Fe+3O_2 -> 2Fe_2O_3

4:Fe:4

6:O_2:6

You actually have the same number of Fe on both sides, The same is true for O_2 so yes this equation is properly balanced.

For added benefit consider the following equation:

CH_4+O_2-> CO_2+2H_2O

ASK: Is this equation balanced? Quick answer: No

ASK: So how do we know and how do we then balance it?

DO: Count the number of each atom type you have on each side of the equation:

1:C:1

4:H:4

2:O:4

As you can see everything is balanced except for O To balance O we can simply add a coefficient of 2 in front of O_2 on the left side which would result in 4 O atoms:

CH_4+color(red)(2)O_2-> CO_2+2H_2O

1:C:1

4:H:4

4:O:4

Everything is now balanced.

Step-by-step explanation:

5 0

2 years ago