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2 years ago

10

The image of the point (-8, -9) under a translation is (-11, -14). Find the

1 answer:

hjlf2 years ago

5 0

Answer:

N

Step-by-step explanation:

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Andre owns a computer backup service. He charges his customers $2.50 for each backup CD. His expenses include $875 for the CD re

alukav5142 [94]

Answer:

$p =2.15n - 875$

Step-by-step explanation:

Given

$CD_s= n$

$Charges = 2.50$ per CD

<u>Expenses</u>

$E_1 = 875$

$E_2 = 0.35$ per CD

Required

The profit (p)

First, calculate the total income on n CDs

$Total = Charges * n$

$Total = 2.50 * n$

$Total = 2.50n$

Next, the expenses on n CDs

$Expenses = E_1 + E_2 * n$

$Expenses = 875 + 0.35 * n$

$Expenses = 875 + 0.35n$

The profit (p) is:

$p = Total - Expenses$

$p =2.50n - (875 + 0.35n)$

Open bracket

$p =2.50n - 875 - 0.35n$

Collect like terms

$p =2.50n - 0.35n - 875$

$p =2.15n - 875$

3 0

3 years ago

Ilia_Sergeevich [38]

Problem 1 Answer: $x=10$

<u>Simplify both sides of the equation</u>

<u></u> $(2)(x)+(2)(-3)=14(Distribute)$ <u></u>

<u></u> $2x+-6=14$ <u></u>

<u></u> $2x-6=14$ <u></u>

<u></u>

<u>Add 6 to both sides</u>

$2x-6+6=14+6$

$2x=20$

<u></u>

<u>Divide both sides by 2</u>

<u></u> $2x/2=20/2$ <u></u>

<u></u> $x=10$ <u></u>

----------------------------------------------------------------

Problem 2 Answer: $x=-7$

<u></u>

<u>Simplify both sides of the equation</u>

<u></u> $(-5)(x)+(-5)(-1)=40(Distribute)$ <u></u>

<u></u> $-5x+5=40$ <u></u>

<u></u>

<u>Subtract 5 from both sides</u>

<u></u> $-5x+5-5=40-5$ <u></u>

<u></u> $-5x=35$ <u></u>

<u></u>

<u>Divide both sides by -5</u>

<u></u> $-5x/5=35/-5$ <u></u>

<u></u> $x=-7$ <u></u>

----------------------------------------------------------------

Problem 3 Answer: $x=-8$

<u></u>

<u>Simplify both sides of the equation</u>

<u></u> $(12)(x)+(12)(10)=24(Distribute)$ <u></u>

<u></u> $12x+120=24$ <u></u>

<u></u>

<u>Subtract 120 from both sides</u>

<u></u> $12x+120-120=24-120$ <u></u>

<u></u> $12x=-96$ <u></u>

<u></u>

<u>Divide both sides by 12</u>

<u></u> $12x/12=-96/12$ <u></u>

<u></u> $x=-8$ <u></u>

----------------------------------------------------------------

Problem 4 Answer: $x=-1/2$

<u></u>

<u>Move all terms to the left:</u>

<u></u> $2(x+6)-(11)=0$ <u></u>

<u></u>

<u>Multiply parentheses</u>

<u></u> $2x+12-11=0$ <u></u>

<u></u>

<u>Add all the numbers together, and all the variables</u>

<u></u> $2x+1=0$ <u></u>

<u></u>

<u>Move all terms containing x to the left, all other terms to the right</u>

<u></u> $2x=-1\\x=-1/2$ <u></u>

----------------------------------------------------------------

Problem 5 Answer: $x = 44$

3 0

2 years ago

Read 2 more answers

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as

stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

$a=7\ cm\\c=13\ cm$

substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

$169=49+b^{2}$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

we have that

<em>Jayden's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct

6 0

3 years ago

Read 2 more answers

What is the answer to x > 10

givi [52]

Answer:

x = 11 or any number bigger than 10

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Please help ASAP!! Answers are appreciated!!

TEA [102]

The answer is M is about -3.74

3 0

3 years ago