Anybody play apex legends? I need somebody to climb with in comp (I main octane)

In the given the data is not defined so we explain only the above code, but before that, we briefly define working of if the function that can be defined as follows:

The If() function, is used only when one of the logical functions and its value must return the value true. or we can say it only return a true value.
In the above function, a column "Elected" is used that uses other column values to check this column value is equal if this condition is true it will return "yes" value.

8 0

3 years ago

What is the decimal number of binary number 1101011 if the binaryis represented as a(n)

Kruka [31]

Answer:

a. Unsigned integer 107

b. Signed magnitude integer -43

c. One’s complement integer -20

d. Two’s complement integer 21

e. ASCII character k

Explanation:

a) For unsigned integer,

We put this value in representation of binary and put binary number in it.

we will place 1, 2, 4, 8, 16, 32, 64, 128 ...(powers of two)

64 32 16 8 4 2 1

1 1 0 1 0 1 1

The positions at 1 is present,we will add those numbers.In this (64+32+8+2+1) =107 is there.

So,107 will be the representation.

b)For signed magnitude integer,

The representation is just the same,but as signed integers the first bit represent the negative number.

64 32 16 8 4 2 1

1 1 0 1 0 1 1

The first bit is for Negative(-),then we will add other number where 1 is present.In this (32+8+2+1)=43.We will add (-) due to signed integers.

So,-43 will be the representation.

c) For One's complement integer,

We will compliment the bits of binary number.At the place of 1 ,place 0 and at the place of 0,place 1.

1 1 0 1 0 1 1

Compliment 0 0 1 0 1 0 0

Then,We put this value in representation of binary and put binary number in it, we will place 1, 2, 4, 8, 16, 32, 64, 128 ...(powers of two)

64 32 16 8 4 2 1

0 0 1 0 1 0 0

The positions at 1 is present,we will add those numbers.In this (16+8)=20 we will put negative at the starting because of the compliment

So, -20 will be the representation.

d)For Two's complement integer,

After compliment of bits At the place of 1 ,place 0 and at the place of 0,place 1.Then,we add 1 bit to the Least significant bit(Lsb).

1 1 0 1 0 1 1

Compliment 0 0 1 0 1 0 0

Add 1 to Lsb 0 0 1 0 1 0 0

+ 1

Number 0 0 1 0 1 0 1

Then,We put this value in representation of binary and put binary number in it, we will place 1, 2, 4, 8, 16, 32, 64, 128 ...(powers of two)

64 32 16 8 4 2 1

0 0 1 0 1 0 1

The positions at 1 is present,we will add those numbers.In this (16+8+1)=21

So,21 will be the representation.

e. For ASCII character,

First,convert it into decimal

We multiply bits with 2^n,from ascending numbers to 0 to (n-1),and add them

= 1 * 2^6 + 1*2^5 + 0* 2^4 + 1*2^3 + 0* 2^2 + 1*2^1 + 1* 2^0

= 64+32+8+2+1

= 107

Then,we check in Ascii table 107 decimal number's position ,k is there.

So,k will be the representation.

8 0

3 years ago

Rijndael, AES, CCMP are same as well as different. They are same in terms of how encryption is done and different in terms of wh

worty [1.4K]

Answer:

Option (b) is the correct answer to this question.

Explanation:

AES is based on Rijndael Algorithm.

The Rijndael algorithm enables a choice of block sizes and key sizes. The choices are for each of 128, 192, or 256 bits. Once NIST implemented Rijndael for AES, it only specified one block size,128 bits, but maintained three major lengths of selection. IEEE 802.11I go a step and further limits when both the main size and length of the block for 128 bits. It simplifies deployment and relieves users during development from having to make yet again another decision.

Other options are incorrect because they are not related to the given scenario.

8 0

3 years ago