A 91.5 kg football player running east at 2.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

Question

3 years ago

14

erward? PLEASE HELP

2 answers:

Shtirlitz [24] · Answer 1 · 2022-05-26T15:35:25+03:00

7 0

Answer:

.345

Explanation:

pentagon [3] · Answer 2 · 2022-05-26T13:47:26+03:00

Answer:

2.877 m/s

Explanation:

According to the laws of conservation of linear momentum,

the momentum of the moving objects before impact is equal to the momentum of the objects after impact (Assuming no external forces were applied)

Let both players are tackled and moving in V velocity

M and m - masses of the players
U and u - velocities of them respectively (both velocities are towards east direction )

momentum before impact = momentum after impact

→MU + →mu = →(M+ m )v

91.5 * 2.73 + 63.5 * 3.09 = (91.5 + 63.5) * V

→V = 2.877 m/s (To East)