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LuckyWell [14K]
1 year ago
12

Which is brighter in our sky, a star with apparent magnitude 2 or a star with apparent magnitude 7?

Physics
1 answer:
Lina20 [59]1 year ago
7 0

The star with apparent magnitude 2 is more brighter than 7.

To find the answer, we have to know about apparent magnitude.

<h3>What is apparent magnitude?</h3>
  • 100 times as luminous as a star with an apparent brightness of 7 is a star with a magnitude of 2.
  • The apparent magnitude of bigger stars is always smaller.
  • The brightest star in the night sky is Sirius.
  • The brightness of a star or other celestial object perceived from Earth is measured in apparent magnitude (m).
  • The apparent magnitude of an object is determined by its inherent luminosity, its distance from Earth, and any light extinction brought on by interstellar dust in the path of the observer's line of sight.

Thus, we can conclude that, the star with apparent magnitude 2 is more brighter than 7.

Learn more about the apparent magnitude here:

brainly.com/question/350008

#SPJ4

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Answer:

A rectangular object may have different areas for different sides.

If that object is placed on a hand, the area of its side does not affects the Force. However the pressure it puts on the hand is affected by the area.

Explanation:

The Force that object applies on the hand is given as the product of its mass and gravitational acceleration 'g'. Hence area does not affect the Force and it is constant.

F = mg

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An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a cir
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Here,only those radiations will be capable of emitting electrons irrespective of surface barrier of metals whose energy is greater than the work function.

We know that the radiation having long wavelength has least energy as energy and wavelength are inversely proportional to each other.

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Here h is the Planck's constant,c is the velocity of light.

Here we have been given red light and blue light.

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Explanation;

All objects accelerate at the constant rate in the Earth's gravitational field. The gravitational acceleration, g = 9.8 m/s².

Distance traveled by an object falling down under a constant acceleration will be given the formula;

s = ut² + 1/2(gt²); but u the initial velocity is o

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S =1/2(gt²)

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Answer:

a)

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Answer: 9.6 s

Explanation:

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