Answer:
The formula for Impedance for circuit with R, C, and L are:
The impedance Z of the series RLC circuit depend upon angular frequency ω. Impedance is measured in ohms and resistance (R), inductance reactance and capacitive reactance. Series RLC circuit consist of the resistance, a capacitance and an inductance connected in the circuits. Electrical impedance is the measurement of the opposition that a circuit present in a current.
For simplicity, assume that the total mass of the compound is 100 g.
Therefore, by mass
Ca = 24.7 g, H = 1.2 g, C = 14.8 g, and O = 59.3 g
Converting these to moles
Mol = mass*1/atomic mass
Ca = 24.7*1/40.078 =0.6163 mol Ca
H = 1.2*1/1.01 = 1.1881 mol H
C = 14.8*1/12.01 = 1.2323 mol C
O = 59.3/16 = 3.7062 mol O
Next, divide all the mols by the smallest value obtained.
Ca: 0.6163/0.6163 = 1 mol Ca
H: 1.1881/0.6163 = 2 mol H
C: 1.2323/0.6163 = 2mol C
O: 3.7062/0.6163 = 6 mol O
Therefore, empirical formula of the compound is
CaH2C2O6
This compound is referred to as Calcium Bicarbonate
Answer:
Es una constante porque sigue funcionando y debido a la gravedad, tú tendrías que ser tú quien la detenga si está bajando en lugar de hacia arriba.
Explanation:
Answer:
4 m/s²
Explanation:
Given:
Δx = 60 m
v₀ = 2.0 m/s
v = 22 m/s
Find: a
v² = v₀² + 2aΔx
(22 m/s)² = (2.0 m/s)² + 2a (60 m)
a = 4 m/s²
<h2>Hello!</h2>
The answer is: There are 3.42 moles of MgCl2 in 326g of the compound.
<h2>Why?</h2>
Assuming that the compound is MgCl2, we can find how many moles of the compound are in 326 g of the same compound, calculating the molar mass of the compound, so:
Then,
Therefore, to calculate how many moles are in 326 of the compound, we can use the following equation
Hence,
There are 3.42 moles of MgCl2 in 326g of the compound.
Have a nice day!
