Please help and check all that apply and I will mark brainliest if it’s correct

A grocery shopper tosses a(n) 9.4 kg bag of rice into a stationary 19.9 kg grocery cart. The bag hits the cart with a horizontal

IRINA_888 [86]

The final speed of the cart and the bag is 2.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the bag and the cart must be conserved before and after the collision.

Mathematically:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 9.4 kg$ is the mass of the bag of rice

$u_1 = 7.0 m/s$ is the initial velocity of the bag

$m_2 = 19.9 kg$ is the mass of the cart

$u_2 =0 m/s$ is the initial velocity of the cart (at rest)

$v$ is the final combined velocity of the bag and the cart

Re-arranging the equation and solving for v, we find:

$v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(9.4)(7.0)+0}{9.4+19.9}=2.2 m/s$

Learn more about momentum here:

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#LearnwithBrainly

5 0

3 years ago

If vector A=2i+3j-k and vector B=4i+6j-2k. The angle between them will be: a) 0°b)45°c)90°d)60°

melomori [17]

Notice that

B = 4i + 6j - 2k = 2 (2i + 3j - k) = 2A

so both vectors point in the same direction and the angle between them is (A) 0°.

7 0

3 years ago

3. What conclusion can you make about the electric field strength between two parallel plates? Explain your answer referencing P

KIM [24]

Answer:

From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases

Explanation:

I cannot find any attached photo, but we can proceed anyways theoretically.

The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point

i.e

$E=\frac{F}{Q}$

But the force F

$F= \frac{kQ1Q2}{r^2}$

But the electric field intensity due to a point charge Q at a distance r meters away is given by

$E= \frac{\frac{kQ1Q2}{r^2}}{Q} \\\\\E= \frac{Q1}{4\pi er^2 }$

From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases

6 0

3 years ago

What is the minimum speed needed to fire a champagne cork a distance of 11m?

Crank

To start with solving this problem, let us assume a launch angle of 45 degrees since that gives out the maximum range for given initial speed. Also assuming that it was launched at ground level since no initial height was given. Using g = 9.8 m/s^2, the initial velocity is calculated using the formula:

(v sinθ)^2 = (v0 sinθ)^2 – 2 g d

where v is final velocity = 0 at the peak, v0 is the initial velocity, d is distance = 11 m

Rearranging to find for v0: 
v0 = sqrt (d * g/ sin(2 θ))

v0 = 10.383 m/s

8 0

4 years ago

A strontium vapor laser beam is reflected from the surface of a CD onto a wall. The brightest spot is the reflected beam at an a

sladkih [1.3K]

Answer:

$d=1.29*10^{-6}m$