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Sphinxa [80]
3 years ago
14

Help pls it’s urgent

Physics
1 answer:
vaieri [72.5K]3 years ago
4 0

Answer:

decreases, but frequency increases.

Explanation:

Wavelength and frequency are inversely proportional, meaning the higher the frequency, the shorter the wavelength, and the lower the frequency, the longer the wavelength.

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If a moon on jupiter has 1/8 the mass of the earth and 1/2 the earth's radius, what is the acceleration of gravity on the planet
dusya [7]

The formula we can use here is:

g = G m / r^2

where g is gravity, G is gravitational constant, m is mass, and r is radius

Since G is constant, therefore we can equate two situations:

g1 m1 / r1^2 = g2 m2 / r2^2

(10 m/s^2) r1^2 / m1 = g2 * (1/2 r1)^2 / (1/8 m1)

<span>g2 = 5 m/s^2</span>

8 0
4 years ago
Air at 20ºC with a convection heat transfer coefficient of 20 W/m2·K blows over a pond. The surface temperature of the pond is 2
dimulka [17.4K]

Answer:

The heat flux between the surface of the pond and the surrounding air  is<em> 60 W/</em>m^{2}<em> </em>

Explanation:

Heat flux is the rate at which heat energy moves across a surface, it is the heat transferred per unit area of the surface. This can be calculated using the expression in equation 1;

q = Q/A ...............................1

since we are working with the convectional heat transfer coefficient equation 1 become;

q = h (T_{sf} -T_{sd}) ........................2

where q is the  heat flux;

Q is the heat energy that will be transferred;

h is the convectional heat coefficient = 20 W/m^{2}.K;

T_{sf} is the surface temperature = 23^{o}C 23°C + 273.15  = 296.15 K;

T_{sd} is the surrounding temperature = 20^{o}C = 20°C + 273.15  = 293.15 K;

The values are substituted into equation 2;

q = 20 W/m^{2}.K (  296.15 K - 293.15 K)

q = 20 W/m^{2}.K ( 3 K)

q =  60 W/m^{2}

Therefore the heat flux between the surface of the pond and the surrounding air  is 60 W/m^{2}

3 0
4 years ago
Which gas law states that the pressure of a gas decreases when volume is increased and the temperature is unchanged?
rewona [7]
The answer is C Boyle's Law I believe
3 0
4 years ago
Read 2 more answers
To get an electrical current you have to have a ___ ____.
Alexandra [31]

Answer :

<em>cu</em><em>r</em><em>c</em><em>u</em><em>i</em><em>t</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>Source</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>u</em><em>r</em><em>r</em><em>e</em><em>n</em><em>t</em><em> </em><em>.</em>

7 0
3 years ago
Read 2 more answers
The acceleration vector of a particle Q is given by the following acceleration vector a = 4i - 6tJ + sin(.2t)k m/s^2, where t is
natima [27]

Answer:

V(3) =14i^ -34j^ +8.57 k^

S(3) =(25,-45,3.97)

Explanation:

We know that

V =a dt

from t=0 to 3s

V = 4i - 6tJ + sin(.2t)k m/s² dt

V =4t i^ - 3t^2j^ - cos(2t)/2 k^ +C

So we have

V(0) =-1/2 k^ +C =2i -7j +8.4 k

C=2i -7j +8.9k^

V =4t i^ - 3t^2j^ - cos(2t)/2 k^ + 2i -7j +8.9k^

Then putting 3s

V(3) =14i^ -34j^ +8.57 k^

Also

S(t) =V(t) dt

S(t) = 4t i^ - 3t^2j^ - cos(2t)/2 k^ + 2i -7j +8.9k^] dt

S(t)= (2t^2 +2t)i^ - (t^3 +7t) j^ -[sin(2t)/4 - 8.9t] k^ +C =i+3j-5k

So at t= 0 we have

S(0) = C= i+3j-5k

So S(t) =(2t^2 +2t)i^ - (t^3 +7t) j^ -[sin(2t)/4 - 8.9t] k^ +i+3j-5k

When t= 3

S(3) =25i -45j + 3.97k

S(3) =(25,-45,3.97)

7 0
3 years ago
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