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3 years ago

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Technician A says that gaskets are used to fill a space or gap between two objects to prevent leakage from occurring. Technician

B says that there are many types of gaskets including cylinder head gaskets, valve cover gaskets, and timing cover gaskets. Which technician is correct?
A. Technician A only
B. Technician B only
C. Both technicians
D. Neither A nor B.

1 answer:

natta225 [31]3 years ago

4 0

Answer:C

Explanation:the both are telling us more about a gasket

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Answer:

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Explanation:

Given that,

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The power of circuit 1, P₁ = 50 W

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The power of the bulb is given by :

$P = \dfrac{V^2}{R}$

For bulb 1,

$R_1=\dfrac{V^2}{P_1}\\\\R_1=\dfrac{(120)^2}{50}\\\\R_1=288\ \Omega$

For bulb 2,

$R_2=\dfrac{V^2}{P_2}\\\\R_2=\dfrac{(120)^2}{100}\\\\R_2=144\ \Omega$

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2 years ago

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Answer:

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2 years ago

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Two uniform, solid cylinders of radius R and total mass M are connected along their common axis by a short, light rod and rest o

sveta [45]

Explanation:

A) To prove the motion of the center of mass of the cylinders is simple harmonic:

System diagram for given situation is shown in attached Fig. 1

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$a_{x} = -\omega^{2} x$

where aₓ is acceleration when attached cylinders move in horizontal direction:

<h3>PROOF:</h3>

rotational inertia for cylinders is given as:

$I=\frac{1}{2}MR^{2}$ -----(1)

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∑τ = Iα ------(2)

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τ = RF --------(4)

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$RF=\frac{1}{2}MR^{2}\alpha$

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So above equation becomes

$f_{s}=\frac{1}{2}MR\alpha$ ------ (5)

As angular acceleration is related to linear by:

$a= R\alpha$

Eq (5) becomes

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From (3)

∑Fₓ = Maₓ

Fₓ is sum of fs and restoring force that spring exerts:

$\sum F_{x} = f_{s} - kx$ ----(7)

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$f_{s} - kx = Ma_{x}$ [/tex] -----(8)

Using (6) in (8)

$\frac{1}{2}Ma_{x} - kx =Ma_{x}$

$a_{x} = \frac{2k}{3M} x$ --- (9)

For spring mass system

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Equating (9) and (10)

$\omega^{2} = \frac{2k}{3M}$

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then (9) becomes

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This proves that the motion of the center of mass of the cylinders is simple harmonic.

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Time period is related to angular frequency as:

$T=\frac{2\pi }{\omega}$

$T = 2\pi \sqrt{\frac{3M}{2k}$

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Answer:

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