A toy rocket launcher can project a toy rocket at a speed as high as 35.0 m/s.
1 answer:
Answer:
(a) 62.5 m
(b) 7.14 s
Explanation:
initial speed, u = 35 m/s
g = 9.8 m/s^2
(a) Let the rocket raises upto height h and at maximum height the speed is zero.
Use third equation of motion
h = 62.5 m
Thus, the rocket goes upto a height of 62.5 m.
(b) Let the rocket takes time t to reach to maximum height.
By use of first equation of motion
v = u + at
0 = 35 - 9.8 t
t = 3.57 s
The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.
You might be interested in
Answer:
c = 0.4356 J/gK
Explanation:
Given the following data;
Mass = 450 grams
Initial temperature, T1 = 150°C
Final temperature, T2 = 53°C
Quantity of heat = 34500 Joules
To find the specific heat capacity of the metal;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 53 - 150
dt = -97°C
Converting the temperature in Celsius to Kelvin, we have;
dt = 273 + (-97) = 176 Kelvin
Making c the subject of formula, we have;
Substituting into the equation, we have;
c = 0.4356 J/gK