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Ymorist [56]
2 years ago
6

Density of solids What is your hypothesis (or hypotheses) for this experiment?.

Physics
1 answer:
valentina_108 [34]2 years ago
7 0

I formulate a hypothesis based on their observations about what occurs when both the rock and the wood are submerged in water.

<h3 /><h3>What is density?</h3>

Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.

The mass and density relation is given as

mass = density × volume

I study if the volume or density of items determines whether solid objects float or sink in water in this scientific inquiry I did the experiment of density, mass, and volume using a rock and a standard-shaped piece of wood.

It is critical that the chosen piece of wood is larger than the rock and that the rock be tiny enough to fit inside the measuring cylinder. I see both the rock and a chunk of wood.

Hence I formulate a hypothesis based on their observations about what occurs when both the rock and the wood are submerged in water.

To learn more about the density refers to the link;

brainly.com/question/952755

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A circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne
kati45 [8]

Answer:

The average emf that will be induced in the wire loop during the extraction process is 37.9 V

Explanation:

The average emf induced can be calculated from the formula

Emf = -N\frac{\Delta \phi}{\Delta t}

Where N is the number of turns

\Delta \phi is the change in magnetic  flux

\Delta t is the time interval

The change in magnetic flux is given by

\Delta \phi = \phi _{f} - \phi _{i}

Where \phi _{f} is the final magnetic flux

and \phi _{i} is the initial magnetic flux

Magnetic flux is given by the formula

\phi = BAcos(\theta)

Where B is the magnetic field

A is the area

and \theta is the angle between the magnetic field and the area.

Initially, the magnetic field and the area are pointed in the same direction, that is, \theta = 0^{o}

From the question,

B = 1.5 T

and radius = 15.0 cm = 0.15 m

Since it is a circular loop of wire, the area is given by

A = \pi r^{2}

∴ A = \pi (0.15)^{2}

A = 0.0225\pi

∴\phi_{i}  = (1.5)(0.0225\pi)cos(0^{o} )

\phi_{i}  = (1.5)(0.0225\pi)

( NOTE: cos (0^{o}) = 1 )

\phi_{i}  = 0.03375\pi Wb

For \phi_{f}

The field pointed upwards, that is \theta = 90^{o}. Since cos (90^{o}) = 0

Then

\phi_{f} = 0

Hence,

\Delta \phi = 0- 0.03375\pi

\Delta \phi = - 0.03375\pi

From the question

\Delta t = 2.8 ms = 2.8 \times 10^{-3} s

Here, N = 1

Hence,

Emf = -N\frac{\Delta \phi}{\Delta t} becomes

Emf = -(1)\frac{-0.03375\pi}{2.8 \times 10^{-3} }

Emf = 37.9 V

Hence, the average emf that will be induced in the wire loop during the extraction process is 37.9 V.

5 0
3 years ago
What is the ability to complete extended periods of physical activity?
Galina-37 [17]

Answer:

D) WELLNESS

Explanation:

3 0
2 years ago
Read 2 more answers
Help :((((((((((((((((((((
Ann [662]

3-6 seconds time interval is the object slowing down.

The correct option is C.

<h3>What is a time interval?</h3>

The time interval is the span of time among two specified times. To put it another way, it is the amount of time that has passed between the event's start and finish.

<h3>What are different time intervals?</h3>

The time interval is the length of time that the aim uses to gather data and determine values. The critical overview can be one or more seconds, minutes, hours, days, weeks, or months. The period must be greater than zero and positive. When providing minutes, the amount of minutes must divide evenly by 60.

To know more about Time interval visit:

brainly.com/question/28238258

#SPJ13

The complete question is -

During which time interval is the object slowing down ?

a- 8-10 seconds

b- 6-8 seconds

c- 3-6 seconds

d- 0-3 seconds

4 0
1 year ago
Steam enters a well-insulated nozzle at 200 lbf/in.2 , 500F, with a velocity of 200 ft/s and exits at 60 lbf/in.2 with a velocit
Ede4ka [16]

Answer:

386.2^{\circ}F

Explanation:

We are given that

P_1=200lbf/in^2

P_2=60lbf/in^2

v_1=200ft/s

v_2=1700ft/s

T_1=500^{\circ}F

Q=0

C_p=1BTU/lb^{\circ}F

We have to find the exit temperature.

By steady energy flow equation

h_1+v^2_1+Q=h_2+v^2_2

C_pT_1+\frac{P^2_1}{25037}+Q=C_pT_2+\frac{P^2_2}{25037}

1BTU/lb=25037ft^2/s^2

Substitute the values

1\times 500+\frac{(200)^2}{25037}+0=1\times T_2+\frac{(1700)^2}{25037}

500+1.598=T_2+115.4

T_2=500+1.598-115.4

T_2=386.2^{\circ}F

7 0
3 years ago
Best exercises for these topics. <br> (have the amount of exercises, have 4 exercises for each.)
Kipish [7]

Answer:

what is the question?

Explanation:

i dont understand

5 0
2 years ago
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