what is change in internal energy if 30j of heat are released from a system that does 50j of work on its surroundings
1 answer:
Answer:
-80 J
Explanation:
The first law of thermodynamics states that:
where
is the change in internal energy of the system
Q is the heat absorbed by the system
W is the work done by the system
In this problem, we have:
Q = -30 J is the heat released by the system (negative because the system releases it)
W = +50 J is the work done by the system on the surrounding (positive since it is done by the system)
Therefore, the change in internal energy is
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Answer:
4.25 s
Explanation:
Given:
angular acceleration'α'= 1.8 rad/s²
angle 'θ'= 45 rad
time 't'= 4s
initial angular velocity ''=0
as we know that,
θ= t +
45 = 4 + (0.5 x 1.8 x 16)
45- 14.4 = 4
30.6 = 4
= 7.65
Next is to find t by using the equation
=
+
7.65= 0 + (1.8)
= 7.65/1.8
= 4.25 s
Therefore, At the start of 4s interval the motion is at 4.25 second