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Marina CMI [18]
4 years ago
6

Consider a rubber rod having been rubbed with fur to give the rod a net negative charge, and a glass rod having been rubbed with

silk to give it a net positive charge. Compared to their masses before the rods were rubbed with fur and silk,a) both rods have more mass after having been rubbed.b) both rods have less mass after having been rubbed.c) the rubber rod has less mass and the glass rod has more mass than before they were rubbed.d) the rubber rod has more mass and the glass rod has less mass than before they were rubbed.
Physics
1 answer:
butalik [34]4 years ago
6 0

Answer:

D

Explanation:

The rubber rod having been rubbed with fur get a net negative charge thereby gaining more mass which means the mass has increased compared to before it was rubbed against the fur while the glass rod having been rubbed with the silk to give it a net positive has lost mass and therefore has less mass compared to before it was rubbed on the silk.

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What is the mass of 2.47 moles of<br> carbon dioxide CO2 ?
Anna11 [10]

Answer:

CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).

So first finding the mass of 1 molecule of CO2 which is equals to

= mass of 1 carbon atom + masses of 2 oxygen atom, we get

= 12+(16*2)= 12+32= 44 a.m.u.

Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )

1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams

So our answer is 110 grams

6 0
3 years ago
Read 2 more answers
The rate of doing work is called _____.<br> power<br> force<br> energy<br> inertia
balandron [24]
The rate of doing work is called POWER.

Power is also defined as the rate of transfer of energy. It measures the speed of how work is done.

The unit of power is WATT.

Power is computed by dividing WORK DONE by TIME TAKEN.
 P = W/t

1 watt:
*power of a machine
*power of an agent that does work at the rate of 1 joule per secon

1000 watt = 1 kilowatt
1000 kilowatt = 1 megawatt




8 0
3 years ago
Read 2 more answers
Two gratings A and B have slit separations dA and dB, respectively. They are used with the same light and the same observation s
77julia77 [94]

Answer:

a) dB / dA = 2 ,

b) Network B     Network A

        2                         1

        4                         2

        6                         3

Explanation:

a) The expression for grating diffraction is

         d sin θ = m λ

where d the distance between two slits, λ the wavelength and m an integer that represents the diffraction range

In this exercise we are told that the two spectra are in the same position, let's write the expression for each network

Network A

m = 1

         sin θ = 1 λ / dA

Network B

m = 2

        sin θ = 2 λ / dB

they ask us for the relationship between the distances, we match the equations

            λ / dA) = 2 λ / dB

            dB / dA = 2

         

b) let's write the equation of the networks

         sin θ = m_A  λ / dA

         sin θ = m_B  λ / dB

we equalize

           m_A  λ/ dA = m_B  λ / dB

we use that

          dB / dA = 2

           m_A 2 = m_B

therefore the overlapping orders are

Network B     Network A

   2                         1

   4                         2

    6                       3

4 0
3 years ago
Mr. Tolman believes that our universe is expanding, but with all of the gravitational force from the celestial bodies of space,
sattari [20]
The correct answer is A I believe but I may not be correct. Either A or B
8 0
3 years ago
A single loop of area 0.193 m2 is placed perpendicular to a magnetic field of 0.374 T. The loop is rotated about an axis lying i
DENIUS [597]

Answer: The angular speed w of the loop = 181 rad/s

Explanation:

Given that;

Area A = 0.193 m2 

Magnetic field B = 0.374 T

E.m.f = 9.24v

Ø = 45 degree

According to Faraday's law when the magnetic flux linking a circuit changes, an electromotive force is induced in the circuit proportional to the rate of change of the flux linkage.

Using the formula

E.m.f = NABwcosØ

Where w = angular velocity.

Let assume that N = 1 then,

9.24 = 0.193 × 0.374 × w × cos45

9.24 = 0.051w

w = 9.24/0.051

w = 181 m/s

Therefore, the angular speed w of the loop = 181 rad/s

4 0
3 years ago
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