Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
Answer:
x=12, y= 20
Step-by-step explanation:
We can find x using the pythagorean thereom because ABD is a right triangle.(D is the point between segments with legnth 5 and 11)
AC^2 + CD^2 = AD^2
x^2 + 5^2 = 13^2
x^2 = 25 = 169
x^2 = 144
x = 12
We may now find y using the pythagorean thereom because ABC is a right triangle. Right now we know x = 12
AC^2 + CB ^2 = AB^2
12^2 + 16^2 = y^2
144 + 256 = y^2
y^2 = 400
y= 20
<em>I hope this helps! :)</em>
Answer:
180
Step-by-step explanation:
for 40 to be equal to 80 in percentages, the number has to be duplicated
Question four should be -7, question five should be 99, and question six should be 56.
The diagram in the question is a cylinder.
;The volume of a cylinder is given by;
Volume = πr²h
;Where π=3.14
r⇒radius of the base of the cylinder and
h ⇒ height of the cylinder.
∴Volume = 3.14×5²×3
=235.5 ft³
To the nearest cubic = 236 ft³
