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gizmo_the_mogwai [7]
2 years ago
8

Giving brainily if ur correct

Mathematics
2 answers:
sdas [7]2 years ago
6 0
The answer is c hope it was right ???!!,...
yKpoI14uk [10]2 years ago
5 0
The Answer is b I hope that is right
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Answer:

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Step-by-step explanation:

Let the heights of men be the first population and the heights of women be the second population. Then

We have n_{1} = 15, \bar{x}_{1} = 69.4, s_{1} = 3.09 and

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s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(15-1)(3.09)^{2}+(7-1)(2.58)^{2}}{15+7-2} = 8.68

The 99% confidence interval for the true mean difference between the mean height of the men and the mean height of the women is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{15}+\frac{1}{7}}, i.e.,

(69.4-64.9)\pm t_{0.005}2.946\sqrt{\frac{1}{15}+\frac{1}{7}}

where t_{0.005} is the 0.5th quantile of the t distribution with (15+7-2) = 20 degrees of freedom. So  

4.5\pm(-2.845)(2.946)(0.458), i.e.,

(0.6613, 8.3387)

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Mari has a part time job. She earns $7 an hour. She makes at most $143.50 a week. What is the greatest number of hours that she
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In the picture above.

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Using some identities for solution

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32.08h

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