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My name is Ann [436]
3 years ago
13

James is 6 times older than his friend Zach . If Zach added 8 to his age and multiplied this sum by 3 . Write an equation that c

an be used to solve for zachs age in the box below , use Z as the variable .
Mathematics
1 answer:
swat323 years ago
5 0

Given that:

James is 6 times older than his friend Zach, if Zach added 8 to his age and multiplied this sum by 3 .

To find:

The equation that can be used to solve for zach's age.

Solution:

Let the age of zach be Z.

Zach added 8 to his age = Z+8

And multiplied this sum by 3 = 3(Z+8)

James is 6 times older than his friend Zach = 6Z

Now,

6Z=3(Z+8)

6Z-3Z=24

3Z=24

Divide both sides by 3.

Z=8

Therefore, the required equation is 6Z=3(Z+8) is age of zach is 8 years.

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Regression analysis is used to infer about the relationship between two or more variables.

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<u>Method 1:</u>

Using regression analysis the line of best fit is: y=\alpha +\beta x+e

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\alpha =\bar y-\beta \bar x

Here<em> </em>\bar y and \bar x are mean of the <em>y</em> and <em>x</em> values respectively.

\bar y=\frac{\sum y_{i}}{n} \\\bar x=\frac{\sum x_{i}}{n}

The formula to compute the slope is:

\beta =\frac{\sum (x-\bar x)(y - \bar y)}{\sum (x=\bar x)^{2}}

And the formula to compute the error is:

e=y-\alpha -\beta x

<u>Method 2:</u>

The regression line can be determined using the descriptive statistics mean, standard deviation and correlation.

The equation of the line of best fit is:

(y-\bar y)=r\frac{\sigma_{x}}{\sigma_{y}} (x-\bar x)

Here <em>r</em> = correlation coefficient = r=\frac{Cov (x,y)}{\sqrt{\sigma^{2}_{x}\sigma^{2}_{y}} }

\sigma_{x} and \sigma_{y} are standard deviation of <em>x</em> and <em>y</em> respectively.

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3 years ago
What are the common factors of 12 and 28?
AlexFokin [52]

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If you have a savings account, contact your bank and find out the interest rate on that account. (If you don’t have your own acc
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Deposit $625 into a money market account with a 5% rate for 1 year would result in more money.

<h3>The interest rate of the bank</h3>

To do this, we make use of 1.50% interest rate

<h3>The exponential growth equation</h3>

Here, we have:

Initial, a= 625

Rate, r = 1.5%

The exponential growth equation is

A(t) = a * (1 + r)^t

So, we have:

A(t) = 625 * (1 + 1.5%)^t

Evaluate

A(t) = 625 * 1.015^t

Hence, the exponential growth equation is A(t) = 625 * 1.015^t

<h3>The value in 25 years</h3>

Here, t = 25.

So, we have:

A(25) = 625 * 1.015^25

Evaluate

A(25) = 906.84

Hence, the value in 25 years is $906.84

<h3>The investment with more money</h3>

<u>#Investment A</u>

a = 625

r = 1.5%

t = 5

So, we have:

A(5) = 625 * 1.015^5

Evaluate

A(5) = 673.3

<u>#Investment B</u>

a = 625

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So, we have:

A(1) = 625 * 1.5^1

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Hence, deposit $625 into a money market account with a 5% rate for 1 year would result in more money.

Read more about exponential growth equation at:

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