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jenyasd209 [6]
3 years ago
12

Please help. Subject is Pythagorean theorem

Mathematics
1 answer:
pashok25 [27]3 years ago
8 0
3 because I said so and it is correct
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A number that is 7 more than 3 times x
klio [65]
Not sure what the question is but 3x + 7 is the algebraic expression that would represent this statement.
6 0
3 years ago
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What expression shows the distance on the number line between −12 and −1 ?<br><br> Thxxs! ^^
docker41 [41]
-12 and -1 are 11 units apart.
-12-(-1) = -11
The absolute value which is just the number of units is 11. 
Hope this helps you
4 0
3 years ago
Look at pic and answer pls
PtichkaEL [24]

(a)  x^{-5}

(b)  3x^{-7}

(c)  $\frac{4}{3}x^4

Solution:

To write each of the given expression in the form ax^n:

(a)  \frac{x^3}{x^8}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

$\frac{x^3}{x^8}=x^{3-8}

$\frac{x^3}{x^8}=x^{-5}

(b) \frac{6x}{2x^8}

Divide numerator and denominator by the common factor 2, we get

$\frac{6x}{2x^8}=\frac{3x}{x^8}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

      $=3x^{1-8}

$\frac{6x}{2x^8} =3x^{-7}

(c)  \frac{28x^6}{21x^2}

Divide numerator and denominator by the common factor 7, we get

$\frac{28x^6}{21x^2}=\frac{4x^6}{3x^2}

Using exponential rule: \frac{a^x}{a^y}=a^{x-y}

        $=\frac{4}{3}x^{6-2}

$\frac{28x^6}{21x^2}=\frac{4}{3}x^4

8 0
3 years ago
Please help! Limited time!
posledela

Answer:

8

Step-by-step explanation:

Cress to the person below me that’s who I got anwser from hah

7 0
3 years ago
Megan counts by ones to 10. lee counts by fives to 20. who will say more numbers. explain
Arisa [49]
Megan will count more because there are 10 ones in 10, but there are only 4 fives in 20.
7 0
3 years ago
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