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Alekssandra [29.7K]
3 years ago
6

Put these fraction pairs to < > or =. Please answer 1. 1/6 ? 1/8 2. 2/3 ? 4/6

Mathematics
1 answer:
emmainna [20.7K]3 years ago
5 0
#1. 1/6>1/8

#2. 2/3=4/6
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The width of a rectangle is 6n - 2.5 feet and the length is 2.5 + 8 feet. Find the perimeter of the rectangle.
ludmilkaskok [199]

I was thinking the measurement for ;length should be 2.5n + 8 feet since width is 6n -2.5 feet , but you gave 2.5+ 8 feet, so i will solve it in both ways

Answer:  Perimeter =  5 + 12n + 11 feet ; Perimeter =  17n+ 11 feet

Step-by-step explanation:

Using Length = 2.5+ 8 feet,

Perimeter of  a rectangle is calculated as 2( l+ b)

Given that width=6n - 2.5 feet

length =2.5 + 8 feet

Perimeter =2( l+ b)= 2L + 2B

Perimeter= 2(2.5 + 8feet ) + 2( 6n - 2.5 feet)

Perimeter = 5 + 16feet + 12n - 5feet

Perimeter =  5 + 12n + 11 feet

Using Length = 2.5n+ 8 feet,

Perimeter of  a rectangle is calculated as 2( l+ b)

Given that width=6n - 2.5 feet

length =2.5n+ 8 feet

Perimeter =2( l+ b)= 2L + 2B

Perimeter= 2(2.5n + 8feet ) + 2( 6n - 2.5 feet)

Perimeter = 5n + 16feet + 12n - 5feet

Perimeter =  5n + 12n + 11 feet

Perimeter =  17n+ 11 feet

6 0
2 years ago
You had $20 to spend on seven avocados. After buying them you had $6. How much did each avocado cost?
mestny [16]
They each cost 2 dollars

8 0
3 years ago
Read 2 more answers
A rubber ball is dropped from the top of a hole. Exactly 20 seconds later, the sound of the rubber ball hitting bottom is heard.
gayaneshka [121]

9514 1404 393

Answer:

  4192.9 ft

Step-by-step explanation:

We assume your falling-distance formula is supposed to be ...

  s = 16t²

So, the time required to fall distance s is ...

  t = √(s/16) = (1/4)√s

The time required for sound to travel distance s is ...

  s = 1100t

  t = s/1100

Then the sum of the time for the ball to fall and the time for the sound to travel back is ...

  (1/4)√s + s/1100 = 20

  275√s = 22000 -s . . . . . multiply by 1100 and subtract s

  75625s = s^2 -44000s +484,000,000 . . . square both sides

  s^2 -119,625s +484,000,000 = 0 . . . . put in standard form

  s ≈ (1/2)(119,625 ±√12,374,140,625) = {4192.943, 115432.057}

Only the smaller of these two solutions makes any sense in this problem.

The hole is about 4192.9 feet deep.

_____

<em>Additional comment</em>

The distance equation for the falling object presumes a vacuum. The sound transmission presumes the presence of air, so the question setup is self-contradictory.

7 0
3 years ago
Multiply 4 and 7. Then, divide by q.
Makovka662 [10]

Answer:

28/q

Step-by-step explanation:

4 times 7 equals 28 and then divide 28 by q

5 0
3 years ago
A manufacturing plant earned $80 per man-hour of labor when it opened. Each year, the plant earns an additional 5% per man-hour.
baherus [9]

A function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(\mathrm{t})=80 \times 1.05^{\mathrm{t}}

<h3><u>Solution:</u></h3>

Given that  

A manufacturing plant earned $80 per man-hour of labor when it opened.

Each year, the plant earns an additional 5% per man-hour.

Need to write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.  

Amount earned by plant when it is opened = $80 per man-hour

As it is given that each year, the plants earns an additional of 5% per man hour

So Amount earned by plant after one year = $80 + 5% of $80 = 80 ( 1 + 0.05) = (80 x 1.05)

Amount earned by plant after two years is given as:

=(80 \times 1.05)+5 \% \text { of }(80 \times 1.05)=(80 \times 1.05)(1.05)=80 \times 1.052

Similarly Amount earned by plant after three years =80 \times 1.05^{t}

\begin{array}{l}{\Rightarrow \text { Amount earned by plant after } t \text { years }=80 \times 1.05^{t}} \\\\ {\Rightarrow \text { Required function } \mathrm{A}(t)=80 \times 1.05^{t}}\end{array}

Hence a function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(t)=80 \times 1.05^{t}

5 0
3 years ago
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