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GaryK [48]
3 years ago
6

The area of a rectangle is 48 square centimeters and the length of the rectangle is 8 centimeters longer than the width.

Mathematics
1 answer:
Luda [366]3 years ago
8 0
I hope this helps you

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It's 11 because 6+5=11 other words it means it's 11 squares away

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Please help 50 points
sertanlavr [38]

Answer:

2. Georgia colony

3. Massachusetts Bay Colony

4.   New York

5. Charter of Pennsylvania

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7. Swedes colony

8. Rhode Island colony and Connecticut colony

9. New York

10. Plymouth colony

11. Maryland and Virginia colony were both founded in 1776

12. 1732 - 1215 = 517

Hope this helps, could sure use brainliest after this:)

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3 years ago
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Lamar plans to watch 2 movies each month.write an equation represent the total number of movies n that he will watch I m moths
grandymaker [24]

Answer:

n=2m

Step by step:

total=rate of movie watching per month times months

n=2 movies per month times 'm' months, so,

n=2m

4 0
3 years ago
Read 2 more answers
Which statement explains which function shows a greater rate of change?
Bingel [31]

the second statement explains which function shows a greater rate of change

7 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
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