De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
Answer:
g(√x+3)=x Hopefully this helps you answer.
<em><u>The cost of production equation is:</u></em>
C = 10n + 20000
<em><u>Solution:</u></em>
<em><u>The equation representing the cost, C, of producing n tires at Royal Tires Co. can be written as:</u></em>
C = mn + f
Where,
C = cost
n = number of tires
f = company's fixed cost
<em><u>It costs $30,000 to produce 1,000 tires while it costs $50,000 to produce 3,000 tires</u></em>
Therefore,
30, 000 = m(1000) + f
50, 000 = m(3000) + f
Which is,
1000m + f = 30000 ------- eqn 1
3000m + f = 50000 ------- eqn 2
Subtract eqn 1 from eqn 2
3000m + f = 50000
1000m + f = 30000
( - ) -------------------
2000m = 20,000
m = 10
Substitute m = 10 in eqn 1
1000(10) + f = 30000
f = 30000 - 10000
f = 20,000
Thus the equation is:
C = 10n + 20000
Answer:
9/10
Step-by-step explanation:
