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Brilliant_brown [7]
2 years ago
12

Which shows the terms of the series? 4 12 48 192 4 12 36 3 12 48 192 3 12 48

Mathematics
1 answer:
Stells [14]2 years ago
5 0

The value of the term in the series will be equal to 3 + 12 +48 + 192 after calculation.

<h3>What is summation?</h3>

In mathematics, the summation is the addition of a sequence of any kind of numbers, called addends or summands.

Now we have a given term

\sum_{n=1}^{4} 3(4)^{n-1}

By solving the above term;

\sum_{n=1}^{4} 3(4)^{n-1}=3(4)^{1-1}+3(4)^{2-1}+3(4)^{3-1}+3(4)^{4-1}

\sum_{n=1}^{4} 3(4)^{n-1}=3(4)^0+3(4)^1+3(4)^2+3(4)^3

\sum_{n=1}^{4} 3(4)^{n-1}=3 + 12 +48 + 192

Hence the value of the term in the series will be equal to 3 + 12 +48 + 192 after calculation.

To know more about Summation follow

brainly.com/question/2767605

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Answer:

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Step-by-step explanation:

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\mathcal{L}[x]=L

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Apply the inverse Laplace transform with this formula:

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3 years ago
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Kryger [21]

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150 in²

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3 years ago
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3 years ago
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2(4 - 2r) = -2(r + 5)
Alexus [3.1K]
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First, divide both sides by -2. / Your problem should look like: -4 + 2r = r + 5
Second, regroup your terms. / Your problem should look like: 2r - 4 = r + 5
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