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defon
4 years ago
9

A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coi

n is ____-blank
Physics
1 answer:
Fofino [41]4 years ago
8 0

Answer:

0.025 m

Explanation:

The coin completes 18 revolutions in 12 seconds. The angular velocity of the coin is:

\omega = \frac{18 rev}{12 s} \cdot (2\pi \frac{rad}{rev})=9.42 rad/s

The centripetal acceleration of the edge of the coin is given by

a=\omega^2 r

where we have

a = 2.2 m/s^2 is the acceleration

r is the radius of the coin

Solving for r, we find

r=\frac{a}{\omega^2}=\frac{2.2 m/s^2}{(9.42 rad/s^2)^2}=0.025 m

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