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3 years ago

Based on the solubility chart, which of the listed salts is the most soluble at 25 °C?

Physics

2 answers:

Jlenok [28]3 years ago

5 0

Answer:

the anser is d

Explanation:

Black_prince [1.1K]3 years ago

3 0

The best and most correct answer among the choices provided by the question is the first choice "sodium nitrate"

Sodium nitrate is the chemical compound with the formula NaNO₃. This alkali metal nitrate salt is also known as Chile saltpeter or Peru saltpeter to distinguish it from ordinary saltpeter, potassium nitrate.

I hope my answer has come to your help. God bless and have a nice day ahead!

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PLS HELP. WILL GIVE BRAINLIEST. PLS THIS IS WORTH 35 POINTS ON MY TEST

Nata [24]

Answer:

18m/s^2

Explanation:

Vf = Vi + at

t = distance/ average velocity

(120 + 0)/2 = 60 (average velocity)

400m/60m/s = 20/3 s

insert into first equation:

120 = 0 + a(20/3)

360 = 20a

18 = a

HOPE THIS HELPS!!!

5 0

2 years ago

Read 2 more answers

What percent of the world lumber harvest goes to paper production 10% 20% 25% 50%

sergejj [24]

The answer is 50% of the paper production

8 0

3 years ago

A group of students collected the data shown below while attempting to measure the coefficient of static friction (of course, it

anzhelika [568]

Answer:

0.130

Explanation:

From the given data, the coefficient of static friction for each trial are:

1. 0.053

2. 0.081

3. 0.118

4. 0.149

5. 0.180

6. 0.198

The sum of the coefficient of static friction = 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198

= 0.779

So that;

the average coefficient of static friction = $\frac{sum of coefficient of static friction}{number of trials}$

= $\frac{0.779}{6}$

= 0.12983

The average coefficient of static friction is 0.130

8 0

2 years ago

¿Qué resistencia debe ser conectada en paralelo con una de 20 Ω para hacer una

ValentinkaMS [17]

Answer:

60 Ω

Explanation:

R(com) = 15 Ω

1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn

1/15 = 1/20 + 1/R2

1/R2 = 1/15 - 1/20

1/R2 = (4 - 3) / 60

1/R2 = 1/60

R2 = 60 Ω

así, la combinada de resistencia necesaria es 60 Ω

5 0

3 years ago

How much force must you apply to give the go cart an acceleration of 0.9m/s^2

qaws [65]

It's dependent on the mass. You can fimd the force needed using the formula F = ma. Where F is force, m is mass of the cart and a is the acceleration (0.9m/s^2). The heavier it is the more force you are going to need. Remember unit of force is N

5 0

3 years ago