Answer:
2/3
Explanation:
In the case shown above, the result 2/3 is directly related to the fact that the speed of the rocket is proportional to the ratio between the mass of the fluid and the mass of the rocket.
In the case shown in the question above, the momentum will happen due to the influence of the fluid that is in the rocket, which is proportional to the mass and speed of the same rocket. If we consider the constant speed, this will result in an increase in the momentum of the fluid. Based on this and considering that rocket and fluid has momentum in opposite directions we can make the following calculation:
Rocket speed = rocket momentum / rocket mass.
As we saw in the question above, the mass of the rocket is three times greater than that of the rocket in the video. For this reason, we can conclude that the calculation should be done with the rocket in its initial state and another calculation with its final state:
Initial state: Speed = rocket momentum / rocket mass.
Final state: Speed = 2 rocket momentum / 3 rocket mass. -------------> 2/3
First, you need to calculate the resultant force:
R = m · a
= (12.3 + 5.1) · 1.5
= 26.1 N
Then, you can calculate the force of friction:
R = F - Fₐ
Fₐ = F - R
= 33 - 26.1
= 6.9 N
Now, we know that:
Fₐ = μ·m·g
Therefore we can solve for μ:
μ = <span>Fₐ/mg
= 6.9 / (17.4 · 9.8)
= 0.40
The coefficient of dynamic friction is </span>μ = <span>0.40
</span>
Answer:
533.92 m/s
Explanation:
The root-mean-square speed of a gas is given by v = √(3RT/M)
R = molar gas constant = 8.3145 J/mol-K
T = Temperature = 320 K
M = Molar mass of Nitrogen in kg/mol = 2 × 14 × 10⁻³ kg/mol = 28 × 10⁻³ kg/mol
v = √(3RT/M) = √(3 × 8.3145 J/mol-K × 320 K/28 × 10⁻³ kg/mol) = √7981920/28 = √285.068.57 = 533.92 m/s
The total energy remains the same, as long as
none of it escapes the closed system.
