What potential difference vwc between the wire and the cylinder produces an electric field of 2.00Ã104 volts per meter at a dist
ance of 1.20 centimeters from the axis of the wire? (assume that the wire and cylinder are both very long in comparison to their radii.)?
1 answer:
<span>The potential difference Vwc between the wire and the cylinder produces an electric field of 2.00Ã104 volts per meter at a distance of 1.20 centimeters from the axis of the wire is 1160 V</span>
In case of a long wire, electric field E is inversely proportional to r
Therefore E= x/r or x = E*r
Now,
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Answer:
The resultant displacement is 5.8 cm, 31° South of the West axis ⇒ 4th
answer
Explanation:
<u><em>A resultant vector</em></u> is the combination of two or more single vectors
If the two vectors are perpendicular, then
<em><u>The magnitude</u></em> of the resultant vector = ,where
x represents the horizontal vector and y represents the vertical vector
<em><u>The direction</u></em> of the resultant vector is , where α
is the angle between the horizontal vector and the resultant vector
Vector 1 is 5 cm due to West-axis
Vector 2 is 3 cm due to South-axis
We need to find the resultant displacement of them
The West and South are perpendicular
The West is the horizontal vector and South is the vertical vector
The magnitude of the resultant displacement s is:
The direction of the resultant displacement s is:
° south of the west (between the west and
the resultant displacement)
<em>The resultant displacement is 5.8 cm, 31° South of the West axis</em>