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sergeinik [125]
3 years ago
12

Solve 2x-3/5=x+6 ASAP

Mathematics
2 answers:
Aliun [14]3 years ago
5 0

Answer:

Problem 1: \frac{2x-3}{5}=x+6 gives x=-11

Problem 2: 2x-\frac{3}{5}=x+6 gives x=33/5

Step-by-step explanation:

I will do it both ways:

Problem 1:

\frac{2x-3}{5}=x+6

I don't like the fraction so I'm going to clear by multiplying both sides by 5:

2x-3=5(x+6)

Distribute:

2x-3=5x+30

Subtract 2x on both sides:

-3=3x+30

Subtract 30 on both sides:

-33=3x

Divide both sides by 3:

-11=x

Problem 2:

2x-\frac{3}{5}=x+6

Clear the fraction by multiplying both sides by 5:

5(2x-\frac{3}{5})=5(x+6)

Distribute:

10x-3=5x+30

Subtract 5x on both sides:

5x-3=30

Add 3 on both sides:

5x=33

Divide both sides by 5:

x=\frac{33}{5}

julsineya [31]3 years ago
4 0

For this case we must solve the following equation:

\frac {2x-3} {5} = x + 6

Multiplying by 5 on both sides we have:

2x-3 = 5 (x + 6)\\2x-3 = 5x + 30

We add 3 to both sides of the equation:

2x = 5x + 30 + 3\\2x = 5x + 33

Subtracting 5x on both sides:

2x-5x = 33\\-3x = 33

Dividing between -3 on both sides:

x = \frac {33} {- 3}\\x = -11

Answer:

-11

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