Answer:
36
Step-by-step explanation:
Hope this helps!
Answer:
12.8mph
Step-by-step explanation:
Let 'w' represent her walking speed
->if her jogging speed is 8mph faster than her walking speed
Jogging speed= w+8
Using the time equation i.e time = dist/speed
For walking when distance is 8miles
time = dist / speed= 8/w hrs
For jogging when distance is 13miles
time = dist / speed= 13/(w+8) hrs
Equating the time
jog time = walk time
13/(w+8) = 8/w
By cross multiplying it
13w = 8w + 64
5w = 64
w=64/5
w=12.8mph
Therefore, 12.8mph is her walking speed.
U should use friendly numbers when subtracting.......the numbers have to be between 3 and 10
Let 
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so
where 
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is
where 
denotes the CDF of , and 
denotes the inverse CDF. We have
Similarly, because 20% of students obtain less than 40 marks, we have
so that
Then 
are such that
and we find
Answer:
y=4x-3
Step-by-step explanation:
