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Anna007 [38]
3 years ago
14

If matrix A is of the size 2×3 and we are able to add matrix B to A. what must be the size of B be?​

Mathematics
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

6 be because 2×3 =6 so B it will be the given answer

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Please answer, yes, or no.
MAVERICK [17]

Answer:

No if you see this sign means (<) that the number in like this1<2 that 2 is greater than 1 so it would be no because it would be this way 9>7 not 9<7

Step-by-step explanation:

8 0
3 years ago
Simplify the logarithm log2(32)
Rom4ik [11]

let log2 32 = x

then 2^x = 32

but we know 2^5 = 32

therefore, x = 5

6 0
3 years ago
Read 2 more answers
Line segments JK and JL in the xy-coordinate plan both have a common endpoint J(-4,11) and midpoints at M1 (2,16) and M2 (-3,5),
OleMash [197]
The first part of the question is not needed 
we only need to know M1 and M2
(y2-y1)^2+(x2-x1)^2=(your answer)^2
(5-16)^2+(-3-2)^2=(your answer)^2
(-11)^2+(-5)^2=(your answer)^2
121+25=(your answer)^2
146=(your answer)^2
√146=12.0830459735945721
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6 0
3 years ago
A spinner marked A, B, C is spun then a 6-sided die is rolled. What is the probability of getting a B and then a 6.
BigorU [14]

Given:

A spinner marked A, B, C is spun then a 6-sided die is rolled.

To find:

The probability of getting a B and then a 6.

Solution:

We know that,

\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

Total possible values for a spinner are 3. So, the probability of getting B, we get

P(B)=\dfrac{1}{3}

Total possible values for a die are 6. So, the probability of getting 6, we get

P(6)=\dfrac{1}{6}

Now, the probability of getting a B and then a 6 is

P(B,6)=\dfrac{1}{3}\times \dfrac{1}{6}

P(B,6)=\dfrac{1}{18}

The required probability is \dfrac{1}{18}.

Therefore, the correct option is D.

5 0
2 years ago
If the density of a full can is 1.1g/cc what is it’s mass?
podryga [215]
Density  = mass / volume
volume of 1 can =  12 * 40  = 480 cm^3
 1.1 = mass / 480

mass = 528 grams Answer
6 0
3 years ago
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