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Arada [10]
3 years ago
5

Two factory plants are making TV panels. Yesterday, Plant A produced 8000 panels. One percent of the panels from Plant A and 4%

of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 3% ?
Mathematics
1 answer:
Over [174]3 years ago
8 0
8000 from plant A with 1% defective
x        from plant B  with 4% defective
8000 + x = y           with 3% defective

da/a = 0.01 -> 80 = da 
db/b = 0.04 -> db = 0.04b
(da+db)/(a+b) = 0.03

(80+b*0.04)/(8000+b) = 0.03
80+b*0.04 = 0.03*(8000+b)
80+b*0.04 = 240 + 0.03b
80 - 240 = 0.03b - b*0.04
-160 = -0.01b
b = 160/0.01
b = 16000

the panels from the plant b were 16000 


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20 POINTS AND BRAINLIEST
emmainna [20.7K]
To solve this equation we must first plug in 5 for x.

\frac{1}{3}<span> (5 - 4x)
               </span>↓ 
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The next step would be to multiply 4 by 5 to get rid of the parenthesis within our main parenthesis.

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\frac{1}{3} (5 - 20)

The next step would be to subtract both of the numbers within the parenthesis.

\frac{1}{3} (-15)

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8 0
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A contractor combined x tons of a gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that co
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Answer:

The value of x would be \frac{3}{5}y or \frac{3}{8}z

Step-by-step explanation:

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x tons of 10% gravel G mixture is mixed with y ton of 2% gravel G to obtain  5% gravel mixture,

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