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3 years ago

Somebody please help!

Mathematics

2 answers:

Brrunno [24]3 years ago

5 0

Is it a negative 10?

eimsori [14]3 years ago

3 0

If x=9, The answer is -89

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Find the perimeter of quadrilateral ABCD with vertices A(-2,-2), B(-1,3),

drek231 [11]

Answer:

Step-by-step explanation:

Step one

given the coordinates

ABCD with vertices A(-2,-2), B(-1,3), C(5, 3), and D(4, -2)

AB=(-2,-2),(-1,3)

BC=(-1,3), (5, 3)

CD=(5, 3),(4, -2)

DA=(4, -2),(-2,-2)

The distance between points AB=

$AB= \sqrt (x_2-x_1)^2+(y_2-y_1)^2$

$AB= \sqrt (-1+2)^2+(3+2)^2\\\\AB= \sqrt 1^2+(5)^2\\\\AB= \sqrt26\\\\AB=5.1$

The distance between points BC=

$BC= \sqrt (5+1)^2+(3-3)^2\\\\BC= \sqrt 6^2+(0)^2\\\\BC= \sqrt36\\\\BC=6$

The distance between points CD

$CD= \sqrt (4-5)^2+(-2-3)^2\\\\CD= \sqrt -1^2+(-5)^2\\\\CD= \sqrt26\\\\CD=5.1$

The distance between points DA

$DA= \sqrt (4+2)^2+(-2+2)^2\\\\DA= \sqrt 6^2+(0)^2\\\\DA= \sqrt36\\\\DA=6$

Hence the perimeter = 5.1+6+5.1+6

= 22.2

5 0

2 years ago

Suppose a and b are the solutions to the quadratic equation 2x^2-3x-6=0. Find the value of (a+2)(b+2).

KonstantinChe [14]

Answer:

(a+2)(b+2) = 4

Step-by-step explanation:

We are given the following quadratic equation:

$2x^2-3x-6=0$

Let a a and b be the solution of the given quadratic equation.

Solving the equation:

$2x^2-3x-6=0\\\text{Using the quadratic formula}\\\\x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{Comparing the equation to }ax^2 + bx + c = 0\\\text{We have}\\a = 2\\b = -3\\c = -6\\x = \dfrac{3\pm \sqrt{9-4(2)(-6)}}{4} = \dfrac{3\pm \sqrt{57}}{4}\\\\a = \dfrac{3+\sqrt{57}}{4}, b = \dfrac{3-\sqrt{57}}{4}$

We have to find the value of (a+2)(b+2).

Putting the values:

$(a+2)(b+2)\\\\=\bigg(\dfrac{3+\sqrt{57}}{4}+2\bigg)\bigg(\dfrac{3-\sqrt{57}}{4}+2\bigg)\\\\=\bigg(\dfrac{11+\sqrt{57}}{4}\bigg)\bigg(\dfrac{11-\sqrt{57}}{4}\bigg)\\\\=\dfrac{121-57}{156} = \dfrac{64}{16} = 4$

3 0

3 years ago

Solve A = P(1 + rt) for t

tino4ka555 [31]

A=P(1+rt)
A/P=1+rt
A/P-1=rt
AP-P/Pr = t
A-1/r=t

7 0

3 years ago

Read 2 more answers

3 more than the product of 3 and y

Fudgin [204]

Answer:

3y+3

Step-by-step explanation:

pls give brainly

4 0

2 years ago

What is the point slope equation of a line with slope -5 that contains the point (6,3)

ehidna [41]

Step-by-step explanation:

Given

Slope (m) = -5

Point

(x1 , y1) = ( 6 , 3)

So the equation is

y - y1 = m ( x - x1)

y - 3 = -5 ( x - 6)

y - 3 = -5x +30

5x + y = 30 + 3

5x + y = 33

5x + y - 33= 0

Which is the required equation.

Hope it will help you :)

3 0

3 years ago