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AfilCa [17]
3 years ago
7

Derek and Wes take a photograph of a lake at the same angle and the same time of day. Derek's picture comes out with crisp edges

around objects in the photo. Wes's picture seems to blur the outlines of objects due to glare. Which wave phenomenon best explains the differences between the pictures?
Diffraction
Dispersion
Reflection
Polarization
Physics
1 answer:
iren [92.7K]3 years ago
3 0

Answer: Polarization

Explanation:

Probably what happens here is that Derek took his photograph with a polarizing filter (which is helpful to avoid that glare from the surface of water, for example), and Wes took his without that filter.

It is important to note, this kind of filter works with an optical phenomenon called polarization, which consists in the alignment of light (electromagnetic waves) in only one vibrational orientation.

To understand it better:

Normally, electromagnetic waves are not polarized, and the vibration occurs in all planes. However, if we make these waves to vibrate in a single plane, we have polarized light.

<u>This is only possible because electromagnetic waves are transversal waves</u>, hence the oscillation occurs in the transversal direction to the propagation.

Note this is not possible for longitudinal waves (sound), because the oscillation occurs in the same direction as the propagation.

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Where is the best place to store a fire extinguisher on a boat?
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8 0
4 years ago
The question ask:
abruzzese [7]

Answer:

\theta=28.07^{\circ}

Explanation:

Speed of van, v = 28 m/s

Radius of unbanked curve, r = 150 m

Let \theta is the angle with the vertical. In case of banking of road,

T\ cos\theta=mg.............(1)

And

T\ sin\theta=\dfrac{mv^2}{r}..........(2)

From equation (1) and (2) :

tan\theta=\dfrac{v^2}{rg}

tan\theta=\dfrac{(28)^2}{150\times 9.8}

\theta=28.07^{\circ}

So, the string makes an angle of 28.07 degrees with the vertical. Hence, this is the required solution.

4 0
3 years ago
A 2 kg ball with an initial velocity of 10 m/s moves at an angle 60º above the +x-direction. The ball hits a vertical wall and b
kow [346]

Answer:

I = 20 i ^ N s

Explanation:

For this problem let's use the Impulse equation

       I = Δp = m v_{f}- v₀

The impulse and the velocity are vector quantities, let's calculate on each axis, let's decompose the velocity

     cos 60 = vₓ / v

     vₓ = v cos 60

     sin60 = v_{y} / v

     v_{y} = v sin60

     vₓ = 10 cos 60

     v_{y} = 10 sin60

    vₓ = 5.0 m / s

    v_{y} = 8.66 m / s

Let's calculate the impulse on each axis

X axis

     Iₓ = m v_{xf} - m vₓ₀

How the ball bounces

    v_{xf} = - vₓ₀ = vₓ

    Iₓ = 2 m vₓ

    Iₓ = 2 2 5

    Iₓ = 20 N s

Y axis

   I_{y} = m v_{yf} - m vyo

On the axis and the ball does not change direction so

   v_{yf} = vyo

  I_{y} = 0

The total momentum is

   I = Iₓ i ^ + I_{y} j ^

   I = 20 i ^ N s

7 0
3 years ago
A typical tire for a compact car is 22 inches in diameter. If the car is traveling at a speed of 60 mi/hr, find the number of re
Softa [21]

Answer:

rpm= 916.7436 rev/min

Explanation:

First determine the perimeter of the wheel, to know the horizontal distance it travels in a revolution:

perimeter= π×diameter= π × 22 inches × 0.0254(m/inche)= 1.7555m

Time we divide the speed of the car, which is the distance traveled horizontally over time unit, by the perimeter of the wheel that is the horizontal distance traveled in a revolution, this dates us the revolutions over the time unit:

revolutions per time= velocity/perimeter

velocity= (60 mi/hr) × (1609.34m/mi) = 96560m/h

revolutions per time= (96560.6m/h) / (1.7555m)= 55004.614 rev/hr

rpm= (55004.614 rev/hr) × (hr/60min)= 916.7436 rev/min

3 0
4 years ago
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