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vagabundo [1.1K]
3 years ago
12

A cube has a density of 1800 kg/m3 while at rest in the laboratory. What is the cube's density as measured by an experimenter in

the laboratory as the cube moves through the laboratory at 84.0 % of the speed of light in a direction perpendicular to one of its faces? You may want to review
Physics
1 answer:
sashaice [31]3 years ago
8 0

Answer:

3317.44401 kg/m³

Explanation:

\rho' = Actual density of cube = 1800 kg/m³

\rho = Density change due to motion

v = Velocity of cube = 0.84c

c = Speed of light = 3\times 10^8\ m/s

Relativistic density is given by

\rho=\dfrac{\rho'}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow \rho=\dfrac{1800}{\sqrt{1-\dfrac{0.84^2c^2}{c^2}}}\\\Rightarrow \rho=\dfrac{1800}{\sqrt{1-0.84^2}}\\\Rightarrow \rho=3317.44401\ kg/m^3

The cube's density as measured by an experimenter in the laboratory is 3317.44401 kg/m³

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How to find a planet’s gravitational field strength using its radius?
grin007 [14]

The gravitational field strength is approximately equal to 10 N.

<u>Explanation:</u>

Gravitational field strength is the measure of gravitational force acting on any object placed on the surface of the planet. Generally, the mass of the object is considered as 1 kg.

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g = \frac{F}{m}

Here g is the gravitational field strength, m is the mass of the object placed on the surface and F is the gravitational force acting on the object.

Since, the mass of any object placed on the surface of earth will be negligible compared to the mass of Earth, so the mass of the object is considered as 1 kg.

Then the g = F

And F =\frac{GMm}{r^{2} }

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g = F = \frac{6 \times 10^{24} \times 6.67 \times 10^{-11}  \times 1}{(6.6 \times 10^{6}) ^{2} }

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5 0
3 years ago
A ball rolls across a floor with an acceleration of 0.100 m/s2 in a direction opposite to its velocity. The ball has a velocity
Westkost [7]

Answer:

4.15 m/s

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Using the known values in the formula, we get:

2(-0.1)(6)=(4)^{2}- (v_{i})^{2}\\\\ (v_{i})^{2}=16+1.2\\\\ (v_{i})^{2}=17.2\\\\ v_{i}=4.15

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3 0
4 years ago
Describe the relationship between the Law of Conservation of Matter and balancing equations.
Yuliya22 [10]

Answer:

The mass of the products and reactants are the same on both sides of the equation.

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.

3 0
3 years ago
Read 2 more answers
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