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Andrej [43]
2 years ago
8

Earth's crust is formed during ______ and destroyed by ______.

Physics
2 answers:
schepotkina [342]2 years ago
6 0

Answer:

The first one is seafloor spreading and the second is subduction

Explanation:

Sedaia [141]2 years ago
3 0

Answer: sea floor spreading and subduction

Explanation: hopes this helps :)

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What is the net force on an object when you combine a force of 10n north with a force of 5n south?
svetoff [14.1K]
Let north as positive
Fnet=10n-5n
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7 0
3 years ago
The car travels 25 miles in the first 0.5 hours
Westkost [7]

Answer:

\huge\boxed{\sf v = 50\ miles / hr}

Explanation:

<u>Given Data:</u>

Distance = S = 25 miles

Time = t = 0.5 hours

<u>Required:</u>

Speed = v = ?

<u>Formula:</u>

v = S/t

<u>Solution:</u>

v = 25 / 0.5

v = 50 miles / hr

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
4 0
3 years ago
Define Refraction and give some knowlegde about it
shepuryov [24]
Refraction is the change in direction of a wave, caused by the change in the wave's speed. Examples of waves include sound waves and light waves. Refraction is seen most often when a wave passes from one transparent medium to another transparent medium. Different types of medium include air and water. When a wave passes from one transparent medium to another transparent medium, the wave will change its speed and its direction. For example, when a light wave travels through air and then passes into water, the wave will slow and change direction.
7 0
3 years ago
What is the correct answer?
damaskus [11]

Answer:

96 million of dollars

Explanation:

p=-6x^3+72x

p=-6(2)^3+72(2)

p=-6(8)+144

p=-48+144

p=96

8 0
3 years ago
A student throws a baseball horizontally at 25 meters per second from a cliff 45 meters above the level ground. Approximately ho
Delicious77 [7]
First, calculate how long the ball is in midair. This will depend only on the vertical displacement; once the ball hits the ground, projectile motion is over. Since the ball is thrown horizontally, it originally has no vertical speed. 
t = time vi = initial vertical speed = 0m/s g = gravity = -9.8m/s^2 y = vertical displacement = -45m 
y = .5gt^2 [Basically, in this equation we see how long it takes the ball to fall 45m] -45m = .5 (-9.8m/s^2) * t^2 t = 3.03 s 
Now we know that the ball is midair for 3.03s. Since horizontal speed is constant we can simply use: 
x = horizontal displacement v = horizontal speed = 25m/s t = time = 3.03s 
x = v*t x = 25m/s * 3.03s = 75.76 m Thus, the ball goes about 75 or 76 m from the base of the cliff.
8 0
4 years ago
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