Sand. sand is much lighter and can be carried further
Answer:

Explanation:
Given
-- Mass of the boy
-- Mass of the girl
-- Acceleration of the girl towards the boy
Required
Determine the acceleration of the boy towards the girl (
)
From the question, we understand that the surface is frictionless. This implies that the system is internal and the relationship between the given and required parameters is:

Substitute values for
and 

Make
the subject




<em>Hence, the acceleration of the boy towards the girl is 1.446m/s^2</em>
Answer:
Honda won by 0.14 s
Explanation:
We are given that
Distance =S=200 m
Initial velocity of Honda=u=0m/s
Initial velocity of Porsche=u'=0m/s
Acceleration of Honda=
Acceleration of Porsche's=
Time taken by Honda to start=1 s

Substitute the values




Time taken by Honda=11.55 s
Now, time taken by Porsche



Total time taken by Porsche=10.69+1=11.69 s
Because it start 1 s late
Time taken by Honda is less than Porsche .Therefore, Honda won and
Time =11.69-11.55=0.14 s
Honda won by 0.14 s
Answer:
(a) the average acceleration of the bus while braking is 8.333 m/s
(b) if the bus took twice as long to stop, the acceleration will be half of the value obtained in part a. [¹/₂ (8.333 m/s) = 4.16 s]
Explanation:
Given;
initial velocity of the bus, v = 25 m/s
time of the motion, t = 3 s
(a) the average acceleration of the bus while braking
a = dv/dt
where;
a is the bus acceleration
dv is change in velocity
dt is change in time
a = 25 / 3
a = 8.333 m/s
(b) If the bus took twice as long to stop, the duration = 2 x 3s
a = 25 / (2 x 3s)
a = ¹/₂ x (25 / 3)
a = ¹/₂ (8.333 m/s) = 4.16 s
Thus, if the bus took twice as long to stop, the acceleration will be half of the value obtained in part a.
Answer:
0.26 m/s^2
Explanation:
We're asked to find the acceleration of a body given the net force acting on it and it's mass.
To do this, we use Newton's second law.