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Andrej [43]
2 years ago
8

Earth's crust is formed during ______ and destroyed by ______.

Physics
2 answers:
schepotkina [342]2 years ago
6 0

Answer:

The first one is seafloor spreading and the second is subduction

Explanation:

Sedaia [141]2 years ago
3 0

Answer: sea floor spreading and subduction

Explanation: hopes this helps :)

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A gyroscope flywheel of radius 1.96 cm is accelerated from rest at 13.0 rad/s2 until its angular speed is 2270 rev/min. (a) What
nika2105 [10]

Tangential acceleration of a point on the rim of the flywheel during this spin-up process is 0.2548 m/s².

Tangential acceleration is defined as the rate of change of tangential velocity of the matter in the circular path.

Given,

Radius of flywheel (r) = 1.96 cm = 0.0196m

Angular acceleration (α)= 13.0 rad/s²

The tangential acceleration formula is at=rα

where, α is the angular acceleration, and r is the radius of the circle.

using the formula; at=rα  = (13.0 rad/s²) (0.0196m) = 0.2548 m/s².

The tangential acceleration is 0.2548 m/s².

Learn more about the Tangential acceleration with the help of the following link:

brainly.com/question/15743294

#SPJ4

5 0
2 years ago
One anthem of silicon can properly be combined in a compound with
Darya [45]
One atom of silicon can properly be combined in a compound withtwo atoms of oxygen to produce silicon dioxide because silicon is very similar to carbon, as it is in the same group as carbon is in, therefore, it is able to make four bonds.
Moreover, Silicon has 4 valence electrons. In order to form an ionic bond, silicon<span> would have to gain or lose 4 electrons.</span>
4 0
3 years ago
Which of the following formulas represents an olefin (aka alkaline)
pochemuha

Answer:C2H4

Explanation:

Olefins are alkenes, c2h4 is the simplest member called ethene

4 0
4 years ago
You and your little cousin sit on a see-saw. You sit 0.5 m from the fulcrum, and your cousin sits 1.5 m from the fulcrum. You we
svetoff [14.1K]

Answer:

200N

Explanation:

0.5/1.5=x/600N

1/3=x/600

x=200N

7 0
3 years ago
A 1400 kg car driving at 25 m/s slams on its brakes. The coefficient of kinetic friction between the tires and the road is 0.7.
tamaranim1 [39]

The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

The given parameters;

  • mass of the car, m = 1400 kg
  • Initial velocity of the car, u = 25 m/s
  • coefficient of kinetic friction, μ = 0.7

The acceleration of the car is calculated as follows;

a = μg

a = 0.7 x 9.8

a = 6.86 m/s²

The time taken for the car to stop is calculated by using Newton's second law of motion;

F = ma

F = \frac{mv}{t} \\\\ma = \frac{mv}{t}\\\\a = \frac{v}{t} \\\\t = \frac{v}{a} \\\\t = \frac{25}{6.86} \\\\t = 3.64 \ s

Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

Learn more here:brainly.com/question/19887955

5 0
3 years ago
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