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miss Akunina [59]
3 years ago
14

A school holds classes from 8:00 A.M to 2:00 P.M. For what percent of 24-hour day does this school hold classes?

Mathematics
2 answers:
lesya [120]3 years ago
5 0

Answer:

25%

Step-by-step explanation:

So first we need to find out how many hours the school has class. Its 4 hours from 8 to noon, then another 2 from noon to 2. This means the school has class 6 hours a day.

Now we need to figure out the percent. we need to have hours of school over total hours or 6/24

6/24

we can simplify this by dividing both sides by 6

(6/6)/(24/6)=1/4

1/4 is 25%

The school holds class for 25% of the day

scoray [572]3 years ago
5 0

Answer:

25%

Step-by-step explanation:

8:00-2:00=6 hours

6hr/24hr simplifies to 1/4 which is 25%

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Veronika [31]

43 tens = 43 x 10 = 430

3 tens = 3 x 10 = 30

Multiply the two numbers together

430 x 30 = 12900

12900 is your answer

hope this helps

5 0
3 years ago
The table shows a proportional relationship. X -4 -2 0 8 Y-6 -3 0 12. Y=
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Answer: Y= the vertical line of the graph.


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3 years ago
Use a transformation to solve the equation. w/4 = 8 can you also leave a detailed explanation on how this equation = 32
OverLord2011 [107]

Answer:

w=32

Step-by-step explanation:

w/4 = 8

4/1 * w/4 = 8*4

w=32

5 0
3 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Delaney scored -15 points in a word game. Find the opposite of this integer
-Dominant- [34]

Answer:

positive 15

Step-by-step explanation:

opposite of negative is positive

8 0
3 years ago
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