Ask question

Ask question

All categories

3 years ago

11

a man walks for 45 minutes at a rate of 3 mi/h then jogs for 75 minutes at a rate of 5 mi/h then rests for 30 minutes and finall

y walks for 90 minutes at a rate of 3 mi/h. Write a piecewise-defined function expressing the distance he traveled as a function of time.

1 answer:

love history [14]3 years ago

8 0

Answer:

Sorry need points

Step-by-step explanation:

You might be interested in

The price of the product decreased by 10%and then decreased by 20% . calculate total percentage change between the final and ini

aev [14]

What is percentage change?

By quantifying the difference between two numbers and expressing it as an increase or decrease, the Percentage Change Calculator (percent change calculator) may determine the percentage change.

The initial price $V_{1}$ (100%) was decreased by 10%., then this reduced price is reduced more by 20% that becomes the final price $V_{2}$ which is 72.

Calculate percentage change from $V_{1}=100$ to $V_{2}=72$ .

= $& \frac{\left(V_{2}-V_{1}\right)}{\left|V_{1}\right|} \times 100 \\$

$=& \frac{(72-100)}{|100|} \times 100 \\$

$=& \frac{-28}{100} \times 100 \\$

$=&-0.28 \times 100 \\$

$=&-28 \% \text { change } \\$

$=& 28 \% \text { decrease }$

To know more about percentage change visit:

brainly.com/question/7568722

#SPJ4

7 0

2 years ago

A merchant wants to establish the selling price of an item that costs him $4.50 with a 15% markup. What is his selling price?

OLga [1]

Answer:

the answer it $5.18

Step-by-step explanation:

$4.50 + ($4.50 x .15)

$4.50 + $0.68 = $5.18

4 0

3 years ago

The table shows the height of a plant as it grows.

viva [34]

Answer

144

Step-by-step explanation:

12*12

3 0

3 years ago

A video game that costs $30 is on sale for 25% off. What is the sale price?

blondinia [14]

If it is on sane for 25% off, that's the same as being on sale for 75% of the original price.

Multiply the original cost by 75% in decimal form.

30*.75=22.5
Final answer: $22.50

8 0

4 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

4 years ago