In a survey of 2,200 people who owned a certain type of car, 1,210 said they would buy that type of car again. What percent of
1 answer:
Answer:
55%
If 1,210 people would buy that type of car again, they were satisfied with it.
The fraction of people who were satisfied would be .
To find a percentage, we need to divide the top of the fraction by the bottom, then multiply by 100.
1210/2200 is equal to 0.55. This is the decimal form of the fraction, but we need the percentage.
0.55 x 100 is equal to 55.
The answer is 55%
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Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that
15% of people have Rh- factor
This means that
52% of people have type O or Rh- factor.
This means that
a. Find the probability that a person has both type O blood and the Rh- factor.
This is
With what we have
0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Answer:
The value of the equation .
Step-by-step explanation:
Consider the provided equation.
We need to solve the provided equation for y.
Subtract 3x from both side.
Divide both sides by 7.
Hence, the value of the equation is .