Answer:
90 days.
Step-by-step explanation:
dy/dt = - 0.0032y
dy = -0.0032y dt
dy/y = -0.0032 dt
Integrating:
ln y = -0.0032t + c where c is some constant
y = e^(-0032t) + e^c
y = A e^(-0032t) where A is a constant.
At time 0 we can let y = 1 so in that case A = 1
When there is 0.75 of y left:
0.75 = e^-0032t
ln 0,75 = -0032 t
t = ln 0.75 / -0032
t = 90.
40 divided by 5 is 8. 8*2= 16.
The vet saw 16 cats.
Answer:
Jack needs to run at a speed of 1/12 mph
Step-by-step explanation:
Mathematically;
speed = distance/ time
Distance = speed * time
10 minutes = 10/60 h = 1/6 hours
The distance to the school will be
Distance = 3 * 1/6 = 1/2 = 0.5 miles
Now, he needs to be at school 4 minutes earlier, time will now be 10 - 4 = 6 minutes
To get the speed here;
Recall that the distance from above does not change
So speed = 0.5/6 mph 0r 1/12 mph
Answer:
give me a minute to find the answer
