Answer:
7- (y/4)
Step-by-step explanation:
Answer:
a)
if 1 quarter = $ 0.25
1 dime = $ 0.10
1 penny = $ 0.01
so to make the total of $1.08 and its is also required to calculate the number of each coins present without being able to make change for a dollar
therefore we say;
1 Quarter + 8 dimes + 3 penny
: ( 1 × 0.25 ) + ( 8 × 0.10 ) + ( 3 × 0.01 )
: 0.25 + 0.80 + 0.03 = $ 1.08
b)
Now if you have a 4 Quarters, you have change for $1.
If you have 5 dimes, you have change for 2 Quarters.
If you have nickel; one of those can combine with 2 dimes to have a change for a Quarter.
If you have 5 pennies, you have enough change for 1 nickel
Therefore
(4-1)×0.25 + (5-1)×0.1 + (0×0.05) + (5-1)×0.01 = x
(3 × 0.25) + ( 4 × 0.1) + 0 + ( 4 × 0.01) = x
x = 0.75 + 0.4 + 0.04
x = $ 1.19
PROVED
Can you upload another picture, you cannot really see your problem
2.0 + 0.5 + 0.01 hope this helps
P would equal negative three.
