Answer:
(3, 3 )
Step-by-step explanation:
Given the 2 equations
3x - y = 6 → (1)
6x + y = 21 → (2)
Adding the 2 equations term by term will eliminate y, that is
(6x + 3x) + (y - y) = (21 + 6), that is
9x = 27 (divide both sides by 9 )
x = 3
Substitute x = 3 into either (1) or (2) and solve for y
Using (2), then
(6 × 3) + y = 21
18 + y = 21 ( subtract 18 from both sides )
y = 3
Solution is (3, 3 )
Hello :
<span>x² + y² + 14x + 2y + 14 = 0
(x²+14x)+(y²+2y)+14=0
(x²+2(7)(x) +7²) -7² +( y²+(2)(1)y+1²)-1² +14 = 0
(x+7)² +(y+1)² = 6²
the center : (-7,-1) and </span><span>length of the radius is : 6</span>
A: High School P, because it has the lowest <span>σ
B: High School N, because it has the highest mean</span>
